Can the unit step function express e^t between 0 and 2?

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SUMMARY

The discussion focuses on expressing the function f(t) = e^t for the interval 0 < t < 2 using the unit step function. The correct expression is e^t * u(t) - e^t * u(t-2), which effectively captures the behavior of the function by ensuring it is zero outside the specified interval. The initial incorrect guess of e^t * u(t+2) demonstrates a misunderstanding of the unit step function's role in defining the active interval for the function.

PREREQUISITES
  • Understanding of the unit step function (u(t))
  • Knowledge of exponential functions and their properties
  • Familiarity with piecewise functions
  • Basic calculus concepts related to function limits
NEXT STEPS
  • Study the properties and applications of the unit step function in signal processing
  • Learn how to manipulate piecewise functions for different intervals
  • Explore the Laplace transform and its relation to the unit step function
  • Investigate the use of the Heaviside function in control systems
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Students in calculus or differential equations, engineers working with signal processing, and anyone interested in mathematical modeling of functions using step functions.

kasse
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Homework Statement



Express f(t) = e^t, 0<t<2, using the unit step function

2. The attempt at a solution

e^t*u(t-2) is an expression for a graph of the function that is zero until t=2. My guess is

e^t*u(t+2)
 
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That's not a very good guess. That makes f(-1)=e^(-1). You want to subtract two step functions so you get something that's only nonzero between 0 and 2.
 

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