MHB Can These Expressions Be Factored Correctly?

  • Thread starter Thread starter mathdad
  • Start date Start date
AI Thread Summary
The discussion focuses on factoring three algebraic expressions. The first expression, 4u^2 + 25v^2, is confirmed to be irreducible over the integers. The second expression, (81/4) - y^2, is correctly factored into (9/2 - y)(9/2 + y). For the third expression, 8a^3 + 27b^3 + 2a + 3b, the application of the sum of cubes is appropriate, but caution is advised regarding variable names to avoid confusion. The participant expresses a lack of access to a computer and plans to share images of their work for clarity.
mathdad
Messages
1,280
Reaction score
0
Factor the following three questions.

1. 4u^2 + 25v^2

I say this one cannot be factored because the expression is irreducible over the integers.

Right?

2. (81/4) - y^2

Let (81/4) = (9/2)(9/2).

So, (81/4) - y^2 factors out to be (9/2 - y)(9/2 + y).

Right?

3. 8a^3 + 27b^3 + 2a + 3b

I must apply the sum of cubes to the expression 8a^3 + 27b^3 as a first step, right?

If so, then a = 2^3 and b = 3^3 in the sum of cubes, right?

I did not ask for the problems to be solved. I simply want to know if my work is correct or not. If it is wrong, make the corrections and allow me to do the math.
 
Mathematics news on Phys.org
1. Correct.

2. Correct.

3. Yes, apply the sum of cubes formula to $8a^3+27b^3$. Be careful with your variable names. $a$ does not necessarily equal $2^3$. In another post you stated $a=(a+b)$. This is only true if $b=0$. Try choosing different letters for different variables. For example, you may be given to factor

$$125a^3-64b^3$$

Then write

$$p=5a$$ and $$q=4b$$

It makes no real difference what other letters you choose; these letters reflect given values no matter what they are.

It is entirely incorrect to state $a=5a$ and $b=4b$ in the context you are working in. At any rate, those two equations are only true if $a$ and $b$ are equal to $0$

Have you thought of learning $\LaTeX$? :)
 
greg1313 said:
1. Correct.

2. Correct.

3. Yes, apply the sum of cubes formula to $8a^3+27b^3$. Be careful with your variable names. $a$ does not necessarily equal $2^3$. In another post you stated $a=(a+b)$. This is only true if $b=0$. Try choosing different letters for different variables. For example, you may be given to factor

$$125a^3-64b^3$$

Then write

$$p=5a$$ and $$q=4b$$

It makes no real difference what other letters you choose; these letters reflect given values no matter what they are.

It is entirely incorrect to state $a=5a$ and $b=4b$ in the context you are working in. At any rate, those two equations are only true if $a$ and $b$ are equal to $0$

Have you thought of learning $\LaTeX$? :)

I do not have a computer. No time to learn LaTex. I will try to post pictures of my work for easy reading. Thank you for your help.
 
Suppose ,instead of the usual x,y coordinate system with an I basis vector along the x -axis and a corresponding j basis vector along the y-axis we instead have a different pair of basis vectors ,call them e and f along their respective axes. I have seen that this is an important subject in maths My question is what physical applications does such a model apply to? I am asking here because I have devoted quite a lot of time in the past to understanding convectors and the dual...
Fermat's Last Theorem has long been one of the most famous mathematical problems, and is now one of the most famous theorems. It simply states that the equation $$ a^n+b^n=c^n $$ has no solutions with positive integers if ##n>2.## It was named after Pierre de Fermat (1607-1665). The problem itself stems from the book Arithmetica by Diophantus of Alexandria. It gained popularity because Fermat noted in his copy "Cubum autem in duos cubos, aut quadratoquadratum in duos quadratoquadratos, et...
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. In Dirac’s Principles of Quantum Mechanics published in 1930 he introduced a “convenient notation” he referred to as a “delta function” which he treated as a continuum analog to the discrete Kronecker delta. The Kronecker delta is simply the indexed components of the identity operator in matrix algebra Source: https://www.physicsforums.com/insights/what-exactly-is-diracs-delta-function/ by...

Similar threads

Back
Top