Can These Expressions Be Factored Correctly?

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SUMMARY

The discussion focuses on the factorization of three algebraic expressions. The first expression, 4u² + 25v², is confirmed as irreducible over the integers. The second expression, (81/4) - y², is correctly factored into (9/2 - y)(9/2 + y). The third expression, 8a³ + 27b³ + 2a + 3b, requires the application of the sum of cubes formula, with caution advised regarding variable naming conventions. The importance of using distinct variable names is emphasized to avoid confusion in algebraic contexts.

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mathdad
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Factor the following three questions.

1. 4u^2 + 25v^2

I say this one cannot be factored because the expression is irreducible over the integers.

Right?

2. (81/4) - y^2

Let (81/4) = (9/2)(9/2).

So, (81/4) - y^2 factors out to be (9/2 - y)(9/2 + y).

Right?

3. 8a^3 + 27b^3 + 2a + 3b

I must apply the sum of cubes to the expression 8a^3 + 27b^3 as a first step, right?

If so, then a = 2^3 and b = 3^3 in the sum of cubes, right?

I did not ask for the problems to be solved. I simply want to know if my work is correct or not. If it is wrong, make the corrections and allow me to do the math.
 
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1. Correct.

2. Correct.

3. Yes, apply the sum of cubes formula to $8a^3+27b^3$. Be careful with your variable names. $a$ does not necessarily equal $2^3$. In another post you stated $a=(a+b)$. This is only true if $b=0$. Try choosing different letters for different variables. For example, you may be given to factor

$$125a^3-64b^3$$

Then write

$$p=5a$$ and $$q=4b$$

It makes no real difference what other letters you choose; these letters reflect given values no matter what they are.

It is entirely incorrect to state $a=5a$ and $b=4b$ in the context you are working in. At any rate, those two equations are only true if $a$ and $b$ are equal to $0$

Have you thought of learning $\LaTeX$? :)
 
greg1313 said:
1. Correct.

2. Correct.

3. Yes, apply the sum of cubes formula to $8a^3+27b^3$. Be careful with your variable names. $a$ does not necessarily equal $2^3$. In another post you stated $a=(a+b)$. This is only true if $b=0$. Try choosing different letters for different variables. For example, you may be given to factor

$$125a^3-64b^3$$

Then write

$$p=5a$$ and $$q=4b$$

It makes no real difference what other letters you choose; these letters reflect given values no matter what they are.

It is entirely incorrect to state $a=5a$ and $b=4b$ in the context you are working in. At any rate, those two equations are only true if $a$ and $b$ are equal to $0$

Have you thought of learning $\LaTeX$? :)

I do not have a computer. No time to learn LaTex. I will try to post pictures of my work for easy reading. Thank you for your help.
 

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