MHB Can These Expressions Be Factored Correctly?

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The discussion focuses on factoring three algebraic expressions. The first expression, 4u^2 + 25v^2, is confirmed to be irreducible over the integers. The second expression, (81/4) - y^2, is correctly factored into (9/2 - y)(9/2 + y). For the third expression, 8a^3 + 27b^3 + 2a + 3b, the application of the sum of cubes is appropriate, but caution is advised regarding variable names to avoid confusion. The participant expresses a lack of access to a computer and plans to share images of their work for clarity.
mathdad
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Factor the following three questions.

1. 4u^2 + 25v^2

I say this one cannot be factored because the expression is irreducible over the integers.

Right?

2. (81/4) - y^2

Let (81/4) = (9/2)(9/2).

So, (81/4) - y^2 factors out to be (9/2 - y)(9/2 + y).

Right?

3. 8a^3 + 27b^3 + 2a + 3b

I must apply the sum of cubes to the expression 8a^3 + 27b^3 as a first step, right?

If so, then a = 2^3 and b = 3^3 in the sum of cubes, right?

I did not ask for the problems to be solved. I simply want to know if my work is correct or not. If it is wrong, make the corrections and allow me to do the math.
 
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1. Correct.

2. Correct.

3. Yes, apply the sum of cubes formula to $8a^3+27b^3$. Be careful with your variable names. $a$ does not necessarily equal $2^3$. In another post you stated $a=(a+b)$. This is only true if $b=0$. Try choosing different letters for different variables. For example, you may be given to factor

$$125a^3-64b^3$$

Then write

$$p=5a$$ and $$q=4b$$

It makes no real difference what other letters you choose; these letters reflect given values no matter what they are.

It is entirely incorrect to state $a=5a$ and $b=4b$ in the context you are working in. At any rate, those two equations are only true if $a$ and $b$ are equal to $0$

Have you thought of learning $\LaTeX$? :)
 
greg1313 said:
1. Correct.

2. Correct.

3. Yes, apply the sum of cubes formula to $8a^3+27b^3$. Be careful with your variable names. $a$ does not necessarily equal $2^3$. In another post you stated $a=(a+b)$. This is only true if $b=0$. Try choosing different letters for different variables. For example, you may be given to factor

$$125a^3-64b^3$$

Then write

$$p=5a$$ and $$q=4b$$

It makes no real difference what other letters you choose; these letters reflect given values no matter what they are.

It is entirely incorrect to state $a=5a$ and $b=4b$ in the context you are working in. At any rate, those two equations are only true if $a$ and $b$ are equal to $0$

Have you thought of learning $\LaTeX$? :)

I do not have a computer. No time to learn LaTex. I will try to post pictures of my work for easy reading. Thank you for your help.
 
Good morning I have been refreshing my memory about Leibniz differentiation of integrals and found some useful videos from digital-university.org on YouTube. Although the audio quality is poor and the speaker proceeds a bit slowly, the explanations and processes are clear. However, it seems that one video in the Leibniz rule series is missing. While the videos are still present on YouTube, the referring website no longer exists but is preserved on the internet archive...

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