zetafunction
- 371
- 0
given the function (or distribution)
[tex]\sum_{n=0}^{\infty} f(E_n,u )= Z(u)[/tex] for 'f' an arbitrary function and [tex]E_n[/tex] a set of eigenvalues of a certain operator [tex]f (L)[/tex] with L self adjoint so all the eigenvalues are real , could we obtain the form of 'L' from Z(u) ??
[tex]\sum_{n=0}^{\infty} f(E_n,u )= Z(u)[/tex] for 'f' an arbitrary function and [tex]E_n[/tex] a set of eigenvalues of a certain operator [tex]f (L)[/tex] with L self adjoint so all the eigenvalues are real , could we obtain the form of 'L' from Z(u) ??