Can we simplify the integral of a dot product to just the product itself?

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SUMMARY

The discussion centers on the simplification of the integral of a dot product, specifically in the context of magnetic flux represented as the integral of the magnetic field vector \(\vec{B}\) dot the differential area vector \(d\vec{A}\). The conditions under which the integral \(\int_A \vec{B} \cdot d\vec{A}\) can be simplified to the product \(BA\) are clarified, emphasizing the necessity of understanding scalar products in vector calculus. The participants confirm that this simplification is valid when the magnetic field \(\vec{B}\) is constant over the area \(A\) being integrated.

PREREQUISITES
  • Understanding of vector calculus, specifically scalar and vector products.
  • Familiarity with magnetic fields and their representation in physics.
  • Knowledge of integrals and their applications in physics.
  • Basic grasp of differential area elements in vector integration.
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  • Study the properties of scalar and vector products in vector calculus.
  • Learn about magnetic flux and its mathematical representation in electromagnetism.
  • Explore the conditions for simplifying integrals in vector fields.
  • Investigate practical applications of magnetic flux in physics and engineering.
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Students and professionals in physics, particularly those studying electromagnetism, as well as educators seeking to clarify concepts related to vector calculus and magnetic fields.

fredrogers3
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Hello, I have a quick question about integrals of dot products. We are learning about magnetic flux as the integral of b dot da. However, what circumstances must be present where we can simplify this integral into (b*a) and ignore the integral?
 
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You already know the answer:
You know how a scalar product works for vectors right? This is the same thing.
Consider your question in two parts ... you want to know when $$\vec{B}\cdot d\vec{A}=BdA$$ and, at the same time, $$\int_A B.dA = BA$$ ...
 

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