Can x=r solve the equations 1/squareroot(x+1)=x and x^3+x^2=1?

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The discussion centers on solving the equations 1/squareroot(x+1)=x and x^3+x^2=1. The key insight is that the root r of the first equation can be shown to satisfy the second equation through algebraic manipulation. Specifically, rearranging 1/squareroot(x+1)=x leads directly to x^3+x^2=1. The calculation of r to five significant figures can be achieved using simple iteration methods.

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[itex]y=1/squareroot(x+1)[/itex]
[itex]y=x[/itex]

Sketch the two graphs, and indicate on your graph the location of the root r of the equation [itex]1/squareroot(x+1)=x[/itex]. Use algebra and show that x=r can also solve the equation [itex]x^3+x^2=1[/itex]. Calculate r to 5 significant figurees using simple iteration.


Im stuck in the part in bold. I can rearrange [itex]1/squareroot(x+1)=x[/itex] into [itex]x^3+x^2=1[/itex], but how do i show that x=r can solve the equation? Thanks.
 
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hi gomes! :smile:

(have a square-root: √ and try using the X2 icon just above the Reply box :wink:)
gomes. said:
Im stuck in the part in bold. I can rearrange [itex]1/squareroot(x+1)=x[/itex] into [itex]x^3+x^2=1[/itex], but how do i show that x=r can solve the equation? Thanks.

there isn't really anything to prove …

"r is the root of 1/√(x+1) = x" is just another way of saying that 1/√(r+1) = r :wink:
 

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