Can you show me if i did these calculations right?

[graphicer89]

Homework Statement

The specific heat of mercury is .03 cal/g C and its boiling point is 357 C. The specific heat of water is 1 cal/g C. It takes 65 calories of energy to vaporize one gram of mercury and 540*(edit) calories to vaporize 1 gram of water. If both substances begin at room temperature ( about 22 C) does it take more energy to boil a gram of mercury or a gram of water? Show your calculations.


Mercury Calculations:


Water calculations:

The Attempt at a Solution

I will just go straight to the trying to solve it out...

Mercury Calculations...

1 x .03 x ( 357-22) +65 = energy required for mercury
1 x .03 x 335 + 65
1 x 10.05 + 65 =
75.05 ...did i do this right?? by your calculations?


Water Calculations:

1 x 1 x (100 -22) + 540 = energy required for water
1 x 1 x 78 + 540
78+540 =
618 = cal energy required for water...So did i do both right ...
...so basically it required more energy to boil a gram of water...

 

[cepheid]

The 540 for energy of vaporization of water is not consistent with what is given in your problem (430). Aside from that, the calculations seem alright.

 

[graphicer89]

The 540 for energy of vaporization of water is not consistent with what is given in your problem (430). Aside from that, the calculations seem alright.

Your completely right cepheid i messed up ...instead of 430 it should had been 540 ...but does it seem right? now that its 540?

 

[cepheid]

As far as I can see, your calculations look fine. I don't see any obvious errors with the method or with the arithmetic.