Can You Solve This Nonlinear Differential Equation with Cosine Functions?

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Homework Help Overview

The discussion revolves around a nonlinear differential equation involving cosine functions, specifically expressed as λ (dx/dt)² = (cos(α) - x)(cos(β) - x), with x defined as cos(θ). Participants are attempting to verify a proposed solution and explore the steps needed to arrive at it.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants are discussing the validity of the proposed solution and the steps taken to solve the differential equation. There are questions about the substitution used and the relationship between x and cos(θ). Some participants suggest checking the solution by substituting it back into the original equation.

Discussion Status

The discussion is ongoing, with participants offering guidance on checking the solution and questioning the assumptions made regarding the relationship between variables. There is no explicit consensus, but several lines of reasoning are being explored.

Contextual Notes

There are indications of confusion regarding the initial definitions and substitutions, as well as the complexity of the solution provided by Mathematica. Participants are encouraged to share their work to facilitate further discussion.

latentcorpse
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ok so try this guy

[tex]\lambda (\frac{dx}{dt})^{2} = (cos{ \alpha} - x)(cos{ \beta} - x)[/tex]
where [tex]x = cos{ \theta}[/tex]

and the solution is

[tex]x = cos{ \alpha} sin^{2}{\frac{t}{2 \lambda}} + cos{ \beta} cos^{2}{\frac{t}{2 \lambda}}[/tex]

please show you're working cos that's where I am getting lost
 
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maybe I am reading your post wrong, but I don't see any question?
 
Why not show us YOUR working, then maybe we can spot where you are going wrong.
 
ok so the question is to solve the differential equation to try and prove that is indeed the solution.

however all I've managed to do so far is square root everything and crossmultiply - what would u reckoon the substituion is?
 
why do you say that [tex]x = cos{ \theta}[/tex] and then say that the solution is [tex]x = cos{ \alpha} sin^{2}{\frac{t}{2 \lambda}} + cos{ \beta} cos^{2}{\frac{t}{2 \lambda}}[/tex], that doesn't make sense to me.

But it should be farely easy to check that it is a solution, just put x in on both sides and see if they agree.
 
yeah god point i think that's a mistake

ok. forget the x = cos(theta) part
 
maybe it is not, maybe I just misread it in my head, you can of cause find theta by

[tex]x = cos^{-1}[cos{ \alpha} sin^{2}{\frac{t}{2 \lambda}} + cos{ \beta} cos^{2}{\frac{t}{2 \lambda}}][/tex]

and that makes sense. But I don't understand why you just don't check it yourself? And if you can't get all the way through show us what you have done and we will try to correct you if it is wrong, or simply help you further
 
mathematica gives me a novella for an answer so if you have an analytic soln be clearer about it
 

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