Can You Taylor Expand a Dual Integral with Variable Limits?

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SUMMARY

The discussion focuses on the challenge of performing a Taylor expansion of a dual integral with variable limits, specifically for the function F[a,b] = ∫_{y_a}^{y_b} ∫_{x_a}^{x_b} dx dy f[x,y]. The user encounters significant difficulties with numerical integration in Mathematica, which takes approximately 20 minutes, and seeks an analytic solution. The limits of integration, x_a and x_b, are functions of (a,b,y), complicating the Taylor expansion process. The leading order contributions of (a,b) are identified as a^{-2} and b^{0}.

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Hepth
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Assume I have a function:
f[x,y]
This function has two real values (a,b) that are very small O(0).

My end result should be:

<br /> F[a,b] = \int_{y_a}^{y_b} \int_{x_a}^{x_b} dx dy f[x,y] <br />
Whereupon I would then expand F about a=0 and b=0.

Now my problem is that the integration is very difficult. So much so that mathematica takes about 20 minutes to do the full dual integral, and I really end up doing a numerical integration. But I need an analytic form as well.

My question is, can I somehow taylor expand the original function f[x,y] in (a,b) FIRST, then integrate that? What would I have to do about the limits? xa and xb, the limits of integration for x, are actually functions of (a,b,y) and you and yb are functions of (a,b).
These functions of (a,b) are also non-trivial, may include powers of inverse order.

Is that a clear question? In the end I know (a,b) leading order contributions are of the order a^{-2}, b^{0}


tl;dr : How do I Taylor expand a dual integral whose limits are also functions of the expansion parameter.
 
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