Cannon Ball r(t) - Find Max Ø for Increasing r2

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SUMMARY

The discussion focuses on determining the maximum angle Ø for a cannonball's trajectory such that the distance r(t) from the cannon is always increasing. The key equations involved are r(t) = gt²/2 + v₀t + x₀ and r² = x² + y², where x = rcosØ and y = rsinØ. The condition for r² to increase is established by ensuring dr²/dt > 0, which implies that gravity should not affect the x-direction motion. The analysis leads to the conclusion that the angle Ø must be optimized to maintain this condition throughout the flight.

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Homework Statement



Question: A cannon shoots a ball at angle Ø above the horizontal ground. Neglecting air resistance, and letting r(t) denote the ball's distance from the cannon, What is the largest possible value of Ø if r(t) is to increase throughout the ball's flight? [hint: Write down r2 as x2 + y2, and then find the condition that r2 is always increasing.]

Homework Equations



r(t) = gt2/2 + v0t + x0
r2 = x2 + y2
x = rcosØ
y = rsinØ

The Attempt at a Solution



r2 = (gt2/2 + v0t + x0)(gt2/2 + v0t + x0) = x20 + 2x0v0t + x0gt2 + v20t2 + v0gt3 + g2t4/4 = x2 + y2 = r2(cos2Ø + sin2Ø)

I don't know how to solve for Ø, so that r2 is always increasing.
 
Physics news on Phys.org
1) There shouldn't be any gravity in the x-direction.
2) You have to find dr^2/dt > 0 if r^2 is going to always increase
 

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