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## Homework Statement

**A cannon shoots a ball at an angle [itex]\theta[/itex] above the horizontal ground**

**a)**Neglecting air resistence, find the ball's position (x(t) and y(t)) as a function of time.

**b)**Take the above answer and find an equation for the ball's trajectory y(x).

## Homework Equations

[itex]\frac{dx}{dt}[/itex] = V

_{o}cos([itex]\theta[/itex])

[itex]\frac{dy}{dt}[/itex] = V

_{o}sin([itex]\theta[/itex]) - gt

## The Attempt at a Solution

Okay, so I integrated both sides of both equations and ended up with:

x(t) = V

_{o}cos([itex]\theta[/itex])t

y(t) = V

_{o}sin([itex]\theta[/itex])t - 0.5gt

^{2}

which I'm pretty sure solves part a), but I'm having a lot of trouble finding a function of y in terms of x for part b). I tried messing around with some trigonometric identities but I get nowhere. Any tips?

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