Cannon Fire! Senior Physics Research Project

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SUMMARY

The discussion focuses on a senior physics research project involving projectile motion, specifically a device that launches a cricket ball at an initial velocity of 28 m/s at a 30-degree angle. To determine the time it takes for the ball to reach its maximum height, one must calculate the vertical velocity component using the initial velocity and the launch angle. The time to reach maximum height is then found by dividing this vertical velocity component by the acceleration due to gravity, which is approximately 9.81 m/s².

PREREQUISITES
  • Understanding of projectile motion principles
  • Knowledge of trigonometric functions for angle calculations
  • Familiarity with basic physics concepts such as velocity and acceleration
  • Ability to perform calculations involving gravity (9.81 m/s²)
NEXT STEPS
  • Calculate the vertical velocity component using the formula: V_y = V * sin(θ)
  • Determine the time to reach maximum height using the formula: t = V_y / g
  • Explore the effects of different launch angles on projectile motion
  • Investigate the impact of initial velocity variations on maximum height and range
USEFUL FOR

This discussion is beneficial for physics students, educators in the field of mechanics, and anyone interested in understanding the principles of projectile motion and its calculations.

Michael17
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Cannon Fire!

Can anyone please help me figre this one out;

A senior physics class conducting a research project on projectile motion constructs a device that can launch a cricket ball. The launching device is designed so that the ball can be launced at ground level with an initial velocity of 28m/s at an angle of 30 degrees to the horizontal. At what time will the ball reach its maximum height?
 
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Figure the vertical velocity component from the angle.

Divide by the magnitude of gravity that is acting to slow it down.

That's your time.
 

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