Max Height Achieved by Ball in Physics Project

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SUMMARY

The maximum height achieved by a cricket ball launched at an initial velocity of 28 m/s at an angle of 30 degrees can be calculated using kinematic equations. The relevant equation is H = (v^2 * sin^2(θ)) / (2 * g), where v is the initial velocity, θ is the launch angle, and g is the acceleration due to gravity (9.8 m/s²). Substituting the values, the maximum height is determined to be approximately 40.4 meters. This calculation assumes no air resistance, focusing solely on the principles of projectile motion.

PREREQUISITES
  • Understanding of kinematic equations in physics
  • Knowledge of projectile motion concepts
  • Familiarity with trigonometric functions, particularly sine
  • Basic grasp of gravitational acceleration (9.8 m/s²)
NEXT STEPS
  • Study the derivation of the kinematic equation for maximum height in projectile motion
  • Explore the effects of air resistance on projectile motion
  • Learn about the components of projectile motion, including horizontal and vertical velocities
  • Investigate real-world applications of projectile motion in sports and engineering
USEFUL FOR

Students in physics, educators teaching projectile motion, and anyone interested in the practical applications of kinematics in sports science.

Michael17
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Can anyone please help me figure this question out;

A senior physics class conducting a research project on projectile motion constructs a device that can launch a cricket ball. The launching device is designed so that the ball can be launched at ground level with an initial velocity of 28m/s at an angle of 30 degrees to the horizontal. What is the maximum height that is achieved by the ball, given that the acceleration due to gravity is 9.8m/s and there is no air resistance?
 
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Any Ideas? Have you attempted the problem?
 
Witch kinematics equations do you think would be a good start?
 

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