# Cannon fired at moving car

• jtspenfield
In summary, the cannonball travels a horizontal distance of 30175ft, takes 38.29 seconds to hit the car, and travels a distance of 1684ft from point C before it is hit. If the car is 10ft long, it will take 0.32 seconds for the car to be hit.
jtspenfield

## Homework Statement

A cannon is fired(from pt. A) at an angle of 38deg and with a Vo of 1000 ft/sec. A car leaves (from pt. C) at 30 mph heading towards the cannon. The cannon hits the truck at point B.
a. Determine the horizontal distance R that the cannonball travels to hit the car.
b. How long did it take to hit the car?
c. How far did it travel from point C before it was hit?
d. If length of the car is 10 ft. How long does the car have when it can be hit?

## Homework Equations

X= (Vo^2(sin2theta))/g
X= Xo + (Vo)t
X=Xo +Vot +1/2(Ac)(t^2)
x=Vt

## The Attempt at a Solution

a. Using the first equation, plugging in the initial velocity(1000ft/sec), angle(38) and dividing by gravity(32.152ft/s^2) yields a solution of 30175ft.

b. plugging the distance traveled into the second equation to determine t yields a solution of 38.29s

c. Since the cannon hits the car after 38.29s, then the car must have traveled for that same length of time, initially leaving at 30mph.
Would it be as simple as x=vt to determine the distance? I come up with 1684 ft(after converting from mph to ft/sec) Or is there some way to use simultaneous equations to find Ac, then determine the distance travelled?

d. Not sure how to begin this one, but if the car is 10 ft long, then the time it takes to move 10 ft would seem to be the time when it could be hit.

jtspenfield said:

## Homework Statement

A cannon is fired(from pt. A) at an angle of 38deg and with a Vo of 1000 ft/sec. A car leaves (from pt. C) at 30 mph heading towards the cannon. The cannon hits the truck at point B.
a. Determine the horizontal distance R that the cannonball travels to hit the car.
b. How long did it take to hit the car?
c. How far did it travel from point C before it was hit?
d. If length of the car is 10 ft. How long does the car have when it can be hit?.

Hi jt! Welcome to PF!

I'm not sure what you've done, but it looks suspicious …

The cannonball's horizontal velocity is constant, and is V0.cos38º.

The cannonball's initial vertical velocity is V0.sin38º, and you have to apply the usual equations to find out the time t when that velocity is reduced to zero.

Then the cannonball returns to the road, and hits the car, at time 2t.

I would like to point out that there are several assumptions and variables involved in this scenario that could affect the accuracy of the calculations and results. For example, the initial velocity of the car, the acceleration of the car, and the exact point of impact of the cannonball on the car could all impact the answers to the given questions.

That being said, based on the given information, your calculations and solutions seem reasonable. For part d, you could use the equation x=vt to determine the time it takes for the car to travel 10 ft, and then use that time to determine the distance the car has traveled from point C before it is hit by the cannonball. However, keep in mind that this calculation assumes that the car is moving at a constant velocity of 30 mph, which may not be the case in reality. Therefore, the actual time and distance may vary. It would be beneficial to clarify these assumptions with the person presenting the problem.

## 1. How does a cannon fired at a moving car affect the car's speed?

The impact of a cannon fired at a moving car can vary depending on the size and velocity of the cannonball, as well as the speed and direction of the car. In general, the car's speed will decrease due to the force of the impact pushing against the car's motion. However, if the cannonball hits the car at an angle or if the car is traveling at a high speed, the impact may cause the car to spin or flip, resulting in a more significant decrease in speed.

## 2. Can a cannon fired at a moving car cause it to stop completely?

It is possible for a cannon fired at a moving car to cause it to stop completely, but it would depend on several factors such as the size and velocity of the cannonball, the speed and direction of the car, and the location of the impact on the car. A direct hit to the engine or braking system could potentially stop the car, but it is not a guaranteed outcome.

## 3. What happens if a cannon is fired at a car that is accelerating?

If a cannon is fired at a car that is accelerating, the impact of the cannonball will have a greater effect on the car's speed. This is because the force of the cannonball will be added to the car's own acceleration, resulting in a more significant decrease in speed. The direction of the car's acceleration will also play a role in the outcome of the impact.

## 4. How does the angle of the cannon affect the impact on the car?

The angle at which a cannon is fired at a moving car will greatly impact the outcome of the impact. A direct hit perpendicular to the car's motion will have a more significant effect on the car's speed and direction than a glancing blow at an angle. The angle of the cannon may also determine where the cannonball hits the car, which can affect the car's momentum and speed.

## 5. Can a cannon fired at a moving car cause it to explode?

In most cases, a cannon fired at a moving car will not cause it to explode. However, if the cannonball hits a fuel tank or other combustible material, it could potentially cause an explosion. This is why it is crucial to use caution and proper safety measures when conducting experiments with a cannon and a moving car.

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