- #1

jtspenfield

- 1

- 0

## Homework Statement

A cannon is fired(from pt. A) at an angle of 38deg and with a Vo of 1000 ft/sec. A car leaves (from pt. C) at 30 mph heading towards the cannon. The cannon hits the truck at point B.

a. Determine the horizontal distance R that the cannonball travels to hit the car.

b. How long did it take to hit the car?

c. How far did it travel from point C before it was hit?

d. If length of the car is 10 ft. How long does the car have when it can be hit?

## Homework Equations

X= (Vo^2(sin2theta))/g

X= Xo + (Vo)t

X=Xo +Vot +1/2(Ac)(t^2)

x=Vt

## The Attempt at a Solution

a. Using the first equation, plugging in the initial velocity(1000ft/sec), angle(38) and dividing by gravity(32.152ft/s^2) yields a solution of 30175ft.

b. plugging the distance traveled into the second equation to determine t yields a solution of 38.29s

c. Since the cannon hits the car after 38.29s, then the car must have traveled for that same length of time, initially leaving at 30mph.

Would it be as simple as x=vt to determine the distance? I come up with 1684 ft(after converting from mph to ft/sec) Or is there some way to use simultaneous equations to find Ac, then determine the distance travelled?

d. Not sure how to begin this one, but if the car is 10 ft long, then the time it takes to move 10 ft would seem to be the time when it could be hit.