- #1

Yahaira.Reyes

- 7

- 0

A) what must the minimum muzzle velocity be for the shell to clear the top of the cliff?

B) The ground at the top of the cliff is level, with a constant elevation of 25.0 m above the cannon. Under the conditions of part (A), how far does the shell past the edge of the cliff?

x=x0 + V0t

Vy= v0y-gt

y=y0+v0yt-1/2gt^2

vf^2=vi^2-2ax

I am a little throw off by the kg of the shell. I do not know how to start the prob.