Cantilever BEAM little problem. I have solved almost everything.

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Discussion Overview

The discussion revolves around a problem related to a cantilever beam, focusing on the application of beam deflection equations and the selection of the modulus of elasticity for materials involved. Participants are addressing a homework problem that includes calculations for deflection and slope, as well as material properties.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Technical explanation

Main Points Raised

  • The original poster presents equations for beam deflection and slope, along with boundary conditions and an attempt at a solution.
  • There is a question regarding which modulus of elasticity (E) to use in the deflection equation, specifically whether to use E for steel or aluminum.
  • One participant suggests using E(steel) based on the transformation of dimensions to steel, while questioning the correctness of the original poster's scaling factor (n).
  • Another participant acknowledges a potential correction to the scaling factor (n) and recalculates the moment of inertia (I) based on this adjustment.

Areas of Agreement / Disagreement

Participants generally agree on the use of E(steel) due to the transformation of dimensions, but there is some uncertainty regarding the scaling factor (n) and its implications for the calculations.

Contextual Notes

There are unresolved aspects regarding the correct application of the scaling factor and its effect on the moment of inertia calculation. The discussion does not clarify the implications of using different moduli of elasticity for the materials involved.

wildleaf
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Cantilever BEAM ! little problem. I have solved almost everything.

Homework Statement


The link below has the problem:
http://i52.tinypic.com/2r3bcdc.jpg


Homework Equations


M = E*I(d^2*w/dx^2)
slope = E*I (dw/dy) = integral of E*I(d^2*w/dx) + c1
deflection = E*I * (w) = double integral of E*I(d^2*w/dx) + c1x + c2

Bounding Condition: when x = 0 --> w = 0 and slope = 0
when x = L --> V = 0 and M = 0
Yb = ΣAY / ΣA
I = Σ(I* + Ad^2)i

The Attempt at a Solution


E*I(d^2*w/dx^2) = (-px^2/2) + (pLx) - (pL^2/2)
E*I (dw/dy) = (-px^3/6) +(pLx^2/2) - (pL^3/6) + c1 (c1 = 0 using when x = 0, slope=0)
w = (- p/(24*E*I)) * [x^4 - 4*L*x^3 + 6*L^2*x^2] + c2 (c2 = 0 using when x=0, w = 0)

I then solved for the I knowing that Yb = 9. I had to transform everything to steel, using n = 30 / 10 = 3. The new dimensions for steel become 4" by 18" (which is the same) and for Al = (4+4)*3 = 24" by 18". Then i calculated the I, and got I = 13608 in^4.

THE PROBLEM I HAVE IS THAT I DONT KNOW WHICH MODULUS OF ELASTIC TO USE FOR

w = (- p/(24*E*I)) * [x^4 - 4*L*x^3 + 6*L^2*x^2]

we know that p = 500, L = x = 20, I = 13609, E = ?
 
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wildleaf: You can use E(steel). However, your n value currently looks wrong. Try again.
 


Ohhh... n = 1/3 ?? I always mess that up. If n = 1/3, then I = 3240.

Why do you use E(steel) and not E(Al) ??
 
wildleaf: You use E(steel) because you said you transformed everything to steel.

Your n value now looks correct.
 

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