Capacitance and max field strength of a concentric sphere capacitor

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Homework Help Overview

The problem involves a capacitor formed by two concentric spheres with a liquid insulant, focusing on calculating the capacitance and the maximum electric field strength between the spheres. The parameters include the radii of the spheres, the relative permittivity of the insulant, and the potential difference applied.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to calculate the capacitance using the modified formula that incorporates the relative permittivity. They also explore the calculation of the maximum electric field strength using the charge derived from capacitance and potential difference. Some participants question the relationship between the electric field just outside the inner sphere and the electric field in the gap between the spheres.

Discussion Status

Participants have provided guidance on using Gauss' law to find the electric field and clarified the relationship between the electric field at the inner sphere and in the gap. There is an ongoing exploration of the calculations and their implications.

Contextual Notes

The discussion includes assumptions about the dielectric properties of the insulant and the interpretation of the electric field in relation to the geometry of the capacitor. There is a focus on ensuring the correct application of formulas and understanding the physical principles involved.

Andzus
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Homework Statement


A capacitor is formed by two concentric spheres r1= 30 cm and r2=15 cm, with a liquid insulant between them with relative permittivity Er=4. The potential difference between the spheres is 1 kV.
Find:
1. capacitance
2. maximum field strength in the gap between the two spheres

Homework Equations



C=4*pi*epsilon/[1/r1-1/r2]
Q=C*potential_difference
Emax=Q/4*pi*epsilon*r^2


The Attempt at a Solution


1. To get the capacitance I added Er=4 to the formulae
C=4*pi*Er*epsilon/[1/r1-1/r2]
and got C=133.4 pF, is this right? I added Er=4 because we usually use Er=1[for air]

2. to get the max field strength I substited Q=C*potential_difference into Emax and used r=r1-r2. So now the equation is:
Emax=C*potential_difference/4*pi*Er*epsilon*(r1-r2)^2
and got Emax=2.14
 
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You have a value for capacitance, so you should be able to find the charge on the capacitor given the voltage difference.

Given the charge, the electric field just outside the 15cm radius sphere can be found via Gauss' law.

[tex]E = \frac{Q}{4 \pi \epsilon_0 \epsilon_r r^2}[/tex]
 
gneill said:
You have a value for capacitance, so you should be able to find the charge on the capacitor given the voltage difference.

Given the charge, the electric field just outside the 15cm radius sphere can be found via Gauss' law.

[tex]E = \frac{Q}{4 \pi \epsilon_0 \epsilon_r r^2}[/tex]

Just to clarify - is the maximum electric field just outside the 15cm radius sphere the same as the electric field in the gap between the two spheres?
 
Andzus said:
Just to clarify - is the maximum electric field just outside the 15cm radius sphere the same as the electric field in the gap between the two spheres?

Yes it is. The variable of interest in the equation I provided is r, and it ranges from just above the surface of the inner sphere to just before the inner surface of the outer sphere.
 
gneill said:
Yes it is. The variable of interest in the equation I provided is r, and it ranges from just above the surface of the inner sphere to just before the inner surface of the outer sphere.

Thank You very much gneill! :)
 

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