Capacitance: Explaining Lamp Operation Separated by Insulator

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SUMMARY

The discussion centers on the operation of a lamp in a circuit with a signal generator set at 6.0 Vr.m.s. and 1000 Hz, where a capacitor with an insulator (dielectric) between its plates is used. It is established that the lamp operates normally due to the accumulation of electrons on one plate of the capacitor while the other plate loses electrons to the positive terminal of the power supply. The presence of the dielectric allows for greater charge accumulation, enhancing the circuit's functionality.

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Homework Statement


In the circuit ( signal generator in series with light bulb and capacitor ) the signal generator is set at 6.0 Vr.m.s., 1000 Hz
The lamp operates normally.Explain why the lamp can operate normally when the plates of the capacitor are separated by an insulator.

The Attempt at a Solution



Electrons build up on one of the parallel plates while the other plate loses electrons and they travel to the positive terminal of the power supply.

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Was slightly confused with this question, my course notes say the capacitor always has an insulator separating the plates and wasn't sure if they were expecting an answer with something to do with the type of power supply it was. Thanks for any correspondence.
 
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I assume by insulator you mean dielectric? If that is the case then the insulator would resist the charge so more can accumulate.
 

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