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Homework Statement
The parallel Plates of a capacitor have an area of 2.00 x 10-1m2 a separation distance of 1.00 X 10-2 m and are connected to a 3000 V power supply.
The capacitor is then connected from the supply, and a dielectric is inserted between the plates. We find that the potential difference decreases to 1000 V while the charge on each plate remains constant.
Find the following:
a. original capacitance
b. magnitude of charge
c. capacitance, C after a dielectric is inserted
d. the dielectric constant k of the dielectric
e. permittivity of the dielectric
Homework Equations
a. C=ε0 A/D
b. Q = CΔV ---im not sure
sadly the handouts given to me ends on that chapter on computing magnitude of electric field.
i wanted to know about this badly.
The Attempt at a Solution
a. C=(8.85X10-12 C2(Nm2))(2.00X10-2 m2)/(1.00X10-2 m) = 1.77X10-11
F=1.77 μF
b. Q=CΔV = (1.77X10-11 F)(3000V) = 5.31X10-8 C
this is all i know please help, also please explain things tome or did i messed this up? i know there is google but i really have a lot of things to do. please help.