1. The problem statement, all variables and given/known data The parallel Plates of a capacitor have an area of 2.00 x 10-1m2 a separation distance of 1.00 X 10-2 m and are connected to a 3000 V power supply. The capacitor is then connected from the supply, and a dielectric is inserted between the plates. We find that the potential difference decreases to 1000 V while the charge on each plate remains constant. Find the following: a. original capacitance b. magnitude of charge c. capacitance, C after a dielectric is inserted d. the dielectric constant k of the dielectric e. permittivity of the dielectric 2. Relevant equations a. C=ε0 A/D b. Q = CΔV ---im not sure sadly the handouts given to me ends on that chapter on computing magnitude of electric field. i wanted to know about this badly. 3. The attempt at a solution a. C=(8.85X10-12 C2(Nm2))(2.00X10-2 m2)/(1.00X10-2 m) = 1.77X10-11 F=1.77 μF b. Q=CΔV = (1.77X10-11 F)(3000V) = 5.31X10-8 C this is all i know please help, also please explain things tome or did i messed this up? i know there is google but i really have a lot of things to do. please help.