Capacitance of 3 Hollow Cylinders

Click For Summary

Homework Help Overview

The original poster attempts to find the capacitance of a system consisting of three concentric hollow cylinders with varying radii and charge distributions. The problem involves understanding the electric fields and potential differences between the cylinders, which are connected by a wire.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss treating the system as two capacitors and question how to integrate the electric field to find the potential. There are inquiries about the limits of integration and how to account for the opposing electric fields of the cylinders.

Discussion Status

Some participants have offered guidance on modeling the system as two capacitors and have raised questions about the configuration of the capacitors (series or parallel). The discussion is exploring different interpretations of the setup and how to approach the calculations.

Contextual Notes

There is uncertainty regarding the integration limits and the treatment of the charge distribution among the cylinders. Participants are also considering the implications of the wire connection between the cylinders on their configuration.

adenine7
Messages
10
Reaction score
0

Homework Statement


I'm trying to find the capacitance of a system of 3 concentric hollow cylinders. The first cylinder has radius R, the second radius 2R, the third radius 3R. Cylinders 1 and 3 are connected by a wire. In total, they have charge +λ, and the second cylinder has charge -λ. The cylinders are infinitely long.

Homework Equations


Ehollow cylinder = (1 / 2πεo)*(Q / RL)
C= Q / V

The Attempt at a Solution


Since cylinders 1 and 3 are connected by the wire, the charge will distribute evenly according to surface area. Cylinder 3 has 3 times as much surface area, so it will have charge 3λ/4 (And Cylinder 1 will have charge λ/4).

I know that to solve this problem I must integrate the electric field to find the potential, and use that in C=Q/V to find capacitance. However, I don't really understand what the limits of my integration are. The outer cylinders are positive, so their electric fields point inwards to the middle cylinder. Do I account for their opposite directions (cancelling each other out partially)? Do I just integrate E from R to 3R? Do I need to multiply two oppositely signed integrals by the proportion of charge?

I was thinking of multiplying ∫E from R to 2R by λ/4, and multiplying ∫E from 2R to 3R by 3λ/4, then subtracting those. My believe my biggest trouble is that I don't understand how to deal with more than 2 surfaces for capacitor (and I can't find anything to help me online).
 
Physics news on Phys.org
Have you tried treating the setup as two capacitors?
 
Thanks for the reply!
Ok, so treating it as two capacitors (Where V1 is potential difference for the inner two cylinders and V3 is potential difference for the outer two cylinders):

V1 = -∫R2R Q / 8πεLR dR = -Qln(2) / 8πεL = Qln(1/2) / 8πεL

C= Q / V, so C1 = 8πεL / ln(1/2)

Same thing for C3, except Q is multiplied by 3/4 instead of 1/4.
C3 = 8πεL / 3ln(1/2)

Do I add these together to get the cumulative capacitance of the system?
 
Last edited:
Anyone know how I should proceed?
 
Are the caps connected in series or parallel?
 
I'm not sure I understand the question. The capacitor is 3 concentric cylinders, and the only wire in the problem is connecting the inner and outer cylinders (I guess this means they are connected in series?).
 
You are modelling a single complicated capacitor as an electrically equivalent network of simpler ideal capacitors connected by ideal "wires".
In this case you have two ideal caps - and there are two "wire" connections. (The ideal wires do not have to be physical wires - they can be any conductor that plays the role of equalizing the voltage between two places.)

If you sketch out the series and parallel configurations for two ideal caps, and look at how the charges are distributed between the plates, you should be able to figure out the configuration that is right for you.
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 10 ·
Replies
10
Views
1K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 4 ·
Replies
4
Views
1K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
13
Views
2K
  • · Replies 36 ·
2
Replies
36
Views
2K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 9 ·
Replies
9
Views
4K
  • · Replies 1 ·
Replies
1
Views
2K