Capacitance of a circular capacitor with two parallel dielectrics

[maxipoblete]

Homework Statement

Two circular parallel metallic plates (diameter d) are separated by a distance "h" . Between the plates, there are two parallel dielectrics with constants ε1 and ε2. At the beginning, the plates have a charge Q0 and -Q0. Calculate the capacitance.

Relevant Equations

C=Q/V

Hello, the problem is better illustrated at the picture below.
The capacitor is isolated, with an initial charge Q0. I understand that Q0 does not distribute along the plates homogeneously. How could it be solved with the equivalent parallel circuit?

 

[NascentOxygen]

You could slice it with a vertical cut to create two parallel-plate capacitors where each has its own dielectric constant.

 

[maxipoblete]

You could slice it with a vertical cut to create two parallel-plate capacitors where each has its own dielectric constant.

Yeah that's the idea, but how would the charge split? I believe that it would not be half Q0 and half Q0