inserted how? From which direction?carlyn medona said:inserted to a distance x
Before or after the dielectric is inserted?carlyn medona said:if the capacitor has a charge q
Can you please show your detailed calculation? And a diagram would be helpful as well. Thanks.carlyn medona said:I found effective capacitance which was εw(kx+l-x)÷d and found force to be equal to q^2 d(k-1)÷(2εwl^2)
Assuming the insertion is in the length direction, that looks right to me.carlyn medona said:q^2 d(k-1)÷(2εwl^2)
But is that the "length" direction or the "width" direction? Judging from your reference to l-x it is the length direction.carlyn medona said:It was inserted from top
That's the method I used, getting the same result.carlyn medona said:found force by differentiating energy with respect to distance
A dielectric is a material that does not conduct electricity, but can become polarized when placed in an electric field.
A dielectric placed between parallel plates will experience a force due to the electric field created by the plates. This force is known as the dielectric force and is caused by the polarization of the dielectric material.
The dielectric constant, also known as the relative permittivity, is a measure of how easily a material can be polarized. A higher dielectric constant means that the material can be more easily polarized, resulting in a stronger dielectric force.
Yes, the force on a dielectric placed between parallel plates is inversely proportional to the distance between the plates. This means that as the distance between the plates increases, the force on the dielectric decreases.
The force on a dielectric is dependent on its orientation between the parallel plates. If the dielectric is aligned parallel to the plates, it will experience a greater force than if it is aligned perpendicular to the plates.