Capacitance of concenctric spheres

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Homework Help Overview

The problem involves calculating the equivalent capacitance of a system of six concentric conducting spheres with specified radii. The spheres are connected in pairs by conducting wires, leading to considerations of equipotential surfaces and charge sharing.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the concept of equipotential spheres and how to apply the formula for capacitance to a system of concentric spheres. There are attempts to derive the equivalent capacitance by considering the connections between the spheres and the implications of their radii.

Discussion Status

Some participants are exploring different approaches to find the equivalent capacitance, while others express uncertainty about the correctness of the methods being used. There is an ongoing dialogue about the appropriate equations and how to account for the connections between the spheres.

Contextual Notes

Participants note the challenge of integrating the various radii into the capacitance equations and question the assumptions made regarding the series and parallel configurations of the spheres. There is mention of discrepancies in numerical results, indicating potential misunderstandings in the application of the formulas.

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The figure below shows six concentric conducting spheres, A, B, C, D, E, and F having radii R, 2 R, 4 R, 6 R, 7 R, and 9 R, respectively. Spheres B and C are connected by a conducting wire, as are spheres D and E. Determine the equivalent capacitance of this system.

HWb.jpg


I understand that spheres B and C are equipotentials, as are D and E. Accordingly, they will share their charges with one another.

V = Ke*Q(1/a - 1/b) for a conducting sphere. I plug this into C = Q/V to get C = 1/ke(1/a - 1/b).

My problem is figuring how to knit these radii together into this equation... I guess the spheres which are connected by wire will act as equipotentials, or a capacitor series, and will have equal and opposite charges. This leaves the innermost radius and the outermost to cancel out one another, perhaps...

But I'm trying to find the equivalent capacitance of the system, and I haven't done that with a system of spheres before. In a circuit, Ceq is dependent on the type of connections (series/parallel), here I feel like I'm having to make a few too many assumptions.

I will try solving for Caf, Cbc and Cde, from there I'll have to find Ceq for the total system. Any help would be much appreciated here !
 
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So I think I'm getting closer. I was solving for the same problem with different numbers with R, 2R, 3R, 4R, 5R and 6R. I solved for Caf to get:

1/ke(1/R -1/6R) = 1/ke(5/6R)

Similarly I found Cbc = 1/ke(1/6R) and Cde = 1/ke(1/20R)

From this point I'm really not sure what to do. I went ahead and said Ceq = Caf + Cbc + Cde = 63/60R * 1/ke. The actual answer was 60R/37*1/ke, so I'm doing something essential incorrectly.

Please help!
 
The equation you're searching for is a bit different.

1/Ceq = (1/Cab)+(1/Ccd)+(1/Cef)

You're looking for the capacitance of the system, a series of conductors, while taking into account the irrelevance of certain radii values you see. There are effectively only four conductors in this system: A, the conductor composed of B and C, the conductor composed of D and E, and F. I think for the actual numerical answer, your formula would look something like:

C = (K((1/R - 1/2R)+(1/4R - 1/6R)+(1/7R - 1/9R)))^(-1)
 
I am having similar troubles and I believe that Depric is incorrect. More input would be appreciated.
 

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