Capacitance of concentric shells

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SUMMARY

The discussion focuses on the capacitance of concentric shells, specifically addressing the relationship between voltage on the surfaces of two shells, denoted as 'a' and 'b'. The voltage on the surface of shell 'a' is influenced by the charge distribution on shell 'b', represented mathematically as -Q/(4πεb). Participants clarify that the potential difference (p.d.) is uniform across the surfaces of spherical shells, resolving confusion regarding varying voltages at different positions. A reference link to HyperPhysics is provided for further understanding of Gauss's Law.

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  • Familiarity with Gauss's Law
  • Knowledge of capacitance concepts
  • Basic mathematical skills for manipulating equations involving ε (epsilon) and charge (Q)
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  • Study the application of Gauss's Law in electrostatics
  • Explore the derivation of capacitance formulas for concentric shells
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kenneth1100
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for the part of Capacitance of concentric shells

why Va equals that?


why the voltage on the surface of a is affected by -Q/(4pi*epsilon*b),
which represents the voltage on the surface of b

these two voltage represents something at different position!
 
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thank you
i forgot that V in a shell/sphere is the same as if it's on the surface
I thought the p.d. by the larger shell were different on the surface of the larger shell and on the surface on the smaller shell...
that's why i got trouble

anyway, thanks~
 

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