Capacitors & AC: Changing Phase Difference

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  • Thread starter Thread starter Soumyajit Sarkar
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SUMMARY

Connecting two capacitors in series with an AC source results in a phase difference between voltage and current. A single capacitor introduces a 90-degree phase shift; to achieve a phase difference of 0 degrees, the total impedance must be made entirely real, typically by incorporating resistive elements. The discussion emphasizes the importance of understanding the relationship between voltage and current in capacitive circuits and suggests that the objective may relate to filtering signals or power factor correction.

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  • Understanding of AC circuit theory
  • Knowledge of impedance in electrical components
  • Familiarity with capacitors and their behavior in circuits
  • Basic principles of power factor correction
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  • Research methods for achieving power factor correction in AC circuits
  • Learn about the role of resistors in modifying phase angles in capacitive circuits
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Electrical engineers, circuit designers, and students studying AC circuit behavior, particularly those interested in phase relationships and power factor correction techniques.

Soumyajit Sarkar
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If i connect 2 capacitors in series with an AC source ,and an output ,then how exactly will the phase vary with input source ?

A single capacitor makes a 90 degree phase difference with the current,if I don't want that ,what steps can I can take to change the phase difference to 0 ?
 
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Two linear components in series with impedance Z1 and Z2 behave like a single component with impedance Z1+Z2. Where ##Z=R## or ##Z=j\omega{L}## or ##Z=\frac{1}{j\omega{C}}##, so that is an uninteresting question.

How do you make the phase difference between V and I zero? Make the impedance Z all real, as with a resistor.

You should ask yourself the same question about your bank balance. If you make deposits, then withdrawals in a sinusoidal manner, then the bank balance will vary sinusoidally but 90 degrees out of phase with the account balance. It is the same with electric current versus voltage in L and C.
 
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What exactly are you trying to do? Is this about filtering signals, or power factor correction?
 

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