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What Happens to a Partially Inserted Dielectric in a Capacitor?
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[QUOTE="Patrikp, post: 4961989, member: 529174"] [LIST] [*][B]1. The problem statement,[/B] [/LIST] Dielectric plate is placed in capacitor to the half(picture) and it can freely move. Capacitor consists of two parallel plates and is isolated. Consider two cases: a)charges on plates are constant, b)voltage is constant. What happens in each case? [B] 2. Homework Equations [/B] $$W=\frac{1}{2}CV^2=\frac{q^2}{2C}$$ $$F=\frac{dW}{dx}\\ \text{(1)}$$ $$C=εε[SUB]r[/SUB] \frac{A}{d} $$ [h2]The Attempt at a Solution[/h2] I know that the answer is that the dielectric will be moving inward in both cases and I even have written solution but I don't understand it. I guess that I should find force on dielectric from (2) but before that i need to determine C which I don't know how to do since dielectric is in weird position.[/B] [/QUOTE]
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What Happens to a Partially Inserted Dielectric in a Capacitor?
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