- #1

Titan97

Gold Member

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## Homework Statement

[/B]

Find the power supplied by the battery.

## Homework Equations

$$Z_C=-iX_C$$

$$Z_L=iX_L$$

## The Attempt at a Solution

$$Z_1=R_1-iX_C=\sqrt{R_1^2+X_C^2}e^{i\phi_1}$$

$$Z_2=R_+iX_L=\sqrt{R_2^2+X_L^2}e^{i\phi_2}$$

$$I_1(t)=\frac{V_0}{\sqrt{R_1^2+X_C^2}}e^{i(\omega t-\phi_1)}$$

$$I_2(t)=\frac{V_0}{\sqrt{R_2^2+X_L^2}}e^{i(\omega t-\phi_2)}$$

##\phi_1=\arctan{\frac{12}{5}}##

##\phi_2=\arctan{\frac{4}{3}}##

$$i_{1,rms}=\frac{V_{rms}}{\sqrt{R_1^2+X_C^2}}=10A$$

$$i_{2,rms}=\frac{V_{rms}}{\sqrt{R_2^2+X_L^2}}=13A$$

Power dissipated is ##23\times 130\text{W}##

But the answer given is ##1514\text{W}##