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Capacitor Charge/Discharge boundary conditions for time
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[QUOTE="NascentOxygen, post: 5483968, member: 336970"] At each change of the current, the capacitor voltage equation changes to follow a new curve---here it's a new straight line. A straight line is a linear function of t, but if the graph is rising then t will have a positive coefficient, and if falling t will have a negative coefficient in that section. The steeper the rise or fall, the greater will be the magnitude of the coefficient of t in the describing equation. In each section of the graph, the capacitor voltage usually doesn't start from 0V, it starts with an initial voltage determined by where it ended in the previous section. All of these three considerations must be taken into account when writing each straight-line equation for all the pieces that together describe V[SUB]C[/SUB]. [/QUOTE]
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Capacitor Charge/Discharge boundary conditions for time
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