Capacitor Discharge Time Formula Euler

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SUMMARY

The discussion centers on understanding the calculation of capacitor discharge time using Euler's constant raised to a fractional exponent. The key formula presented is Vc = Vf(1 - e^(-t/T)), where the voltage across the capacitor rises exponentially over time. A specific example is calculated, resulting in a voltage of approximately 958mV, derived from the steps involving e^(-0.212765957). The participants express a need for clearer explanations and resources, particularly in the context of educational materials available in Brazil.

PREREQUISITES
  • Understanding of capacitor charging and discharging principles
  • Familiarity with exponential functions and the Euler constant (e)
  • Basic proficiency in mathematical calculations involving fractional exponents
  • Knowledge of voltage, time constants, and their relationship in electrical circuits
NEXT STEPS
  • Study the derivation of the capacitor charging formula Vc = Vf(1 - e^(-t/T))
  • Learn about the properties of the Euler constant (e) and its applications in exponential decay
  • Explore educational resources or videos specifically addressing fractional exponents in mathematics
  • Investigate common misconceptions in teaching exponential functions and capacitor behavior
USEFUL FOR

Students, educators, and electrical engineers seeking to deepen their understanding of capacitor discharge calculations and the mathematical principles behind exponential functions.

NickTesla
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I would like to understand how the Euler constant elevated to fractional exponent gave this result? 958mV someone please!?
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You did not give enough information for us to check everything, but the calculation is correct (I checked it on my old HP calculator).
 
It is because my doubt is the fractional exponent, do not know why has this result!
958mV no final entendeu!? Obrigado!
 
Personal My question is in Euler's constant raised to a fractional exponent!
Why and how ?? I do not know calculate HP, it's good we mastered without having to use HP,

I have a teaching video, but honestly I still do not understand if you want to see the video? I have!
 
Last edited:
Charging of a capacitor is an exponential
event. Voltage across capacitor rises exponentially as
Vc=Vf(1-e-t/T). Time t is in the exponent, hence the part e-t/T is responsible for the exponential increase in voltage w.r.t time.
 
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OK. Let us take it in steps:
  1. \frac{10}{47}= 0.212765957
  2. e^{-0.212765957}=0.808345302
  3. 1- 0.808345302=0.191655
  4. 5 \cdot 0.191655 = 0.958273
 
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Yes! , I understand, but using numbers,
Watch this video!
 
Svein said:
OK. Let us take it in steps:
  1. \frac{10}{47}= 0.212765957
  2. e^{-0.212765957}=0.808345302
  3. 1- 0.808345302=0.191655
  4. 5 \cdot 0.191655 = 0.958273
 
https://www.youtube.com/watch?v=JHHikLqJuYk
 
  • #10
Svein said:
OK. Let us take it in steps:
  1. \frac{10}{47}= 0.212765957
  2. e^{-0.212765957}=0.808345302
  3. 1- 0.808345302=0.191655
  4. 5 \cdot 0.191655 = 0.958273
Sven Wonderfully Thank you!
 
  • #11
NickTesla said:
Sven Wonderfully Thank you!
Obrigado!
 
  • #12
Personally, I'll be honest, here in South America (Brazil) I doubt that the Brazilian has a video explaining speaking Neper calculation on youtube to calculate the potentiation, constant = e ^ -0.212765957,
I doubt (I dúvi [do] D + O = DO = DEODO talking!). Kkk! I doubt DEODO is when we doubt very much! is the Brazilian way of speaking! My God there are only understand potentiation, that's all, and I going crazy, studying (Mantissa) studies (Mantissa) kkkk lol (mathematics: decimal part of a logarithm) !:book::micoscope:
(Matematicas: decimal part of a logarithm)! I wanted the help of North America, if possible help from the American continent LOL kkkk:oldbiggrin::partytime::bow::headbang::headbang::headbang:

only thing i got! and I get it! Was this here!

but not taught 10 ^ 0,3010

how does it do??:headbang::headbang::headbang::oldgrumpy::oldgrumpy::oldgrumpy:
 
Last edited:

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