Capacitor with a conducting core

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Homework Help Overview

The discussion revolves around a cylindrical capacitor with a solid conducting core and a hollow conducting tube, focusing on calculations related to charge per length, total charge, capacitance, and energy stored. The participants are exploring the correct formulas and values associated with these calculations.

Discussion Character

  • Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to calculate various parameters of the capacitor using specific equations but expresses uncertainty about their correctness. Some participants question the formula used for capacitance, suggesting that the natural logarithm should be in the denominator.

Discussion Status

Participants are actively discussing the correct formula for the capacitance of a cylindrical capacitor. There is a suggestion that the formula presented by the original poster may be incorrect, and a revised formula has been proposed. Guidance has been offered regarding the proper formulation.

Contextual Notes

The original poster has indicated that their calculations are yielding incorrect results, prompting the discussion. There is an emphasis on ensuring the correct application of formulas for the specific geometry of the capacitor.

sonrie
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A 0.380 m long cylindrical capacitor consists of a solid conducting core with a radius of 1.15 mm and an outer hollow conducting tube with an inner radius of 2.05 mm . The two conductors are separated by air and charged to a potential difference of 6.40 V .

Calculate the charge per length for the capacitor.

lambda =_______ C/m.

Calculate the total charge on the capacitor.

Q=_____ C.

Calculate the capacitance.

C=______ F.

Calculate the energy stored in the capacitor when fully charged.

U=_______ J.

Well i figure out a couple of equations to use but i seem to get them wrong! all are wrong! Any Help!
so the equation i used were :



To Find C = 2 pi €o L ln(r2/r1) = 12.22 *10^-12 F = 12.22 pF.
To Find U = (1/2) C V^2 = 250*10^-12 J = 250 pJ.
To Find Q = C V = 78.2*10^-12 C = 78.2 pC
To Find lambda = Q/L = 2.06*10^-10 C/m = 206 pC/m.
 
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sonrie said:
To Find C = 2 pi €o L ln(r2/r1) = 12.22 *10^-12 F = 12.22 pF.

Hi sonrie,

This is the wrong formula for the cylindrical capacitor. The natural log is in the denominator.
 
so the formula should read C= 2 pi Eo L/Ln (r2/r1) Is that correct?
 
That looks right to me.
 
Your the Best! Thank You!
 

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