The capacitance of a parallel plate capacitor is calculated using the formula C = (Kε0A)/d, where A represents the area of the capacitor plates. In the discussion, participants clarify that when analyzing a composite capacitor with multiple dielectrics, each capacitor in the equivalent circuit retains an area A. The confusion arises from the interpretation of the area in relation to the total area of the capacitors involved, which is stated to be 2A. Ultimately, it is established that each capacitor in a series configuration can be treated as having an area A.
PREREQUISITESStudents studying electrical engineering, physics enthusiasts, and professionals involved in circuit design and analysis will benefit from this discussion on capacitance calculations for parallel plate capacitors.
Yes it is mentioned that A=areaNascentOxygen said:
Calculate the capacitance of the parallel plate capacitor shown in the following figure,between points X and Y.ehild said:
That's what it is.ehild said:
I think the transformed circuit diagram by you is correct. Both the capacitors are having area A. You'll have to calculate the equivalent capacitance of the composite capacitor (the one with dielectric constants k2 and k3).gracy said:
But there are 3 capacitors ,right?cnh1995 said:
I'll prefer to call the capacitor on the right as a single capacitor with veriable dielectric constant. There is no metal connection between the dielectrics k2 and k3. So, I don't think they can be a series combination.gracy said:
How in case of three capacitors the area of each capacitor will be A?cnh1995 said:
I believe it means that the area of each side of every metal plate of the equivalent three capacitors here is A.gracy said:
In the case of your equivalent set of three capacitors, each capacitor, C1, C2, and C3 has area A.gracy said:
