How Do You Solve Capacitor Problems Using Kirchhoff's Laws?

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The discussion focuses on solving capacitor problems using Kirchhoff's Laws in a physics context. The original poster expresses confusion about parts b and c of their worksheet, particularly regarding voltage assumptions across a capacitor. Respondents clarify that Kirchhoff's Laws state that the total voltage gained in a circuit must equal the total voltage dropped, emphasizing the relationship between capacitance and voltage. They suggest using the equivalent capacitance of capacitors in parallel to determine voltage drops. Understanding these principles is essential for accurately solving the problem.
AG1189
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Ok here a scanned photo oh my worksheet for physics. I tried and used what I knew for equations to solve. After looking at other sample problems, I am not sure how to find part b and c of the problem. I think I went wrong somewhere. Could someone take a look and guide me in the right direction. ty :smile:

http://img166.imageshack.us/my.php?image=file0001ka0.jpg
 
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Part a looks okay.
Part b, you assumed that there is 24 v across the cap of interest, is this correct? Think about kirchhoffs laws.
 
I have no idea what kirchhoffs laws means, could someone explain it in simple terms
 
Sorry, usually you see k's laws by this point. Basically( in nontechnical terms) , any voltage gained in the circuit must be dropped elsewhere. So you have an emf, or battery if you like, that is rated at 24 volts. This voltage is dropped across the capacitors. How much is dropped is given by the definition of capitance-> c = q/(delta v). Using the equivalent capacitance of each set of caps in parallel will tell you how much voltage is dropped by each pair. Devices in parallel by definition have the same voltage across them.
Really, you should look up kirchhoff's laws, there is too much to explain here.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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