Car hits brick wall, find inital speed of car

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Homework Help Overview

The problem involves an automobile colliding with a brick wall, where the bumper acts as a Hooke's-law spring. Participants are tasked with finding the initial speed of the car based on given mass, spring constant, and compression distance.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the relationship between kinetic energy and the work done by the spring, questioning the application of formulas related to energy transfer during the collision.

Discussion Status

Some participants have offered guidance on using the correct equations to relate the work done by the spring to the change in kinetic energy. There is acknowledgment of errors in calculations and conversions, with some participants confirming the correctness of a derived answer.

Contextual Notes

Participants are working under the constraints of a homework assignment, which may limit the information they can use or the methods they can apply. There is a noted issue with unit conversion that affected initial calculations.

AHinkle
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Homework Statement


An automobile of mass 2000 kg is driven into
a brick wall in a safety test. The bumper
behaves like a Hooke’s-law spring. It has an
effective spring constant of 5 × 106 N/m, and
is observed to compress a distance of 1.67 cm
as the car is brought to rest.
What was the initial speed of the automo-
bile?
Answer in units of m/s.


Homework Equations


\DeltaKE = (1/2)mvf2-(1/2)mvi2
Wapplied to spring=(1/2)kxf2-(1/2)kxi2


The Attempt at a Solution



\Deltax = -0.167m

SPRING.jpg

Wapp=(1/2)kxf2-(1/2)kxi2
Wapp=(1/2)(5x106)(-0.167)2-(1/2)(5x106)(0)2

Wapp = 69722.5 J

Vf = 0 (because the car is brought to rest)
m = 2000 Kg

\DeltaKE = 69722.5 J =(1/2)(2000)(0)2-(1/2)(2000)vi2

69722.5 J = -(1000)vi2
vi2 = (69722.5/-1000)

vi = (-69722.5/1000)1/2

and here i came to a dead end with a non-real answer. Err..
am I at least going in the right direction. I must have my sign off somewhere. I just want to know if I'm approaching the problem correctly.
 
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The change in the kinetic energy of the car, the energy it loses, is transferred to the buckle.
The car goes from v to zero so its change in kinetic energy is simply ½mv²
If the bumper behaves as a Hooke's Law spring, then the energy absorbed by it is given by a formula involving k, the spring constant, and x the distance it compresses.
You have all the information [m,k and x] to calculate v.
Do you know the spring formula?
 
do you mean
Fspring=-kx

and the work done by a spring is
Ws=\int(-kx) dx = 1/2kxf2-1/2kxi2
 
Last edited:
AHinkle said:
do you mean
Fspring=-kx

and the work done by a spring is
Ws=\int(-kx) dx = 1/2kxf2-1/2kxi2

That's it. It's just ½kx² here where x is the compression. Equate the work done to the loss in k.e. of the car.
 
1/2kxf2-1/2kxi2=1/2mvi2

1/2(5x106)(-.0167)2-1/2(5x106)(0)2=1/2(2000)vi2

vi = .835m/s? aww crap... i got a sign or something mixed up somewhere or i just don't understand what orientation i need to put all the parts together in
 
actually i checked the answer and .8350 m/s is correct! I found out what i did wrong. I converted from centimeters to meters incorrectly in my first work calculation and that threw everything off.
 
Yes, the answer is fine. :)
 

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