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Carnot Cycle and Coefficient of Performance
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[QUOTE="bardia sepehrnia, post: 6532281, member: 656138"] [B]Homework Statement:[/B] A refrigeration system is used to cool down water from 15 C temperature and 150 kPa pressure to 5 C at a rate of 0.25 kg/s. Assume the refrigeration system works in a Carnot cycle between 0 C and 40C. Determine: a) The required rate of heat absorbed from the water b) The maximum possible refrigeration system COP c) The amount of power input that a refrigeration system required d) The rate of heat rejected to the atmosphere [B]Relevant Equations:[/B] Q=m*c*deltaT Carnot efficiency = 1-(T_L/T_H) COP=Q_L/W_net,in I think I calculated part a correctly by extracting the cp (specific heat) of water from the table which is 4.188 Then calculated Q_dot by simply using the equation Q=m*c*deltaT=10.47kW But I am stuck at part b, I know that the heat extracted from the water is the same as Q_L (rate of heat absorption from low temp reservoir). But how can I calculate the coefficient of performance (COP) if I don't have Q_H (rate of heat rejection to the high temp reservoir) or W_in (work input) [/QUOTE]
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Carnot Cycle and Coefficient of Performance
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