The discussion focuses on calculating the work done while carrying a 7.0-kg bag of groceries at a constant velocity of 75 cm/s across a distance of 2.3 m and 1.2 m above the floor. The key equation for kinetic energy, KE=(1/2)(m)(v^2), is mentioned but not directly applicable for calculating work in this scenario. The work done can be calculated using the formula Work = Force × Distance, where the force is equal to the weight of the bag acting vertically. The participants emphasize the importance of understanding the direction of the force and the definition of work done in vector terms.
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What force do you apply to the bag for the 2.3m? What direction is that force in? How do you calculate work done based on a force and a distance (preferably as a vector equation)?Timmy1221 said:Homework Statement
- You carry a 7.0-kg bag of groceries 1.2 m above the level floor at a constant velocity of 75 cm/s across a room that is 2.3 m wide. How much work do you do on the bag in the process?
Homework Equations
KE=(1/2)(m)(v^2)
The Attempt at a Solution
I haven't a clue where to start. Any help would be appreciated and thanks!
Start off by writing in words the definition of Work Done that you will need here.Timmy1221 said:Homework Statement
- You carry a 7.0-kg bag of groceries 1.2 m above the level floor at a constant velocity of 75 cm/s across a room that is 2.3 m wide. How much work do you do on the bag in the process?
Homework Equations
KE=(1/2)(m)(v^2)
The Attempt at a Solution
I haven't a clue where to start. Any help would be appreciated and thanks!