- #1

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Express the Cartesian point (3, 3) in polar coordinates.

Do i need to use the sin and cos on my calc.

Any help would be very helpful

lakitu

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- #1

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Express the Cartesian point (3, 3) in polar coordinates.

Do i need to use the sin and cos on my calc.

Any help would be very helpful

lakitu

- #2

arildno

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What is the angle this line segment makes with the positive x-axis?

- #3

PPonte

See- http://en.wikipedia.org/wiki/Polar_coordinates

- #4

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to arildno: Is the angle 45 deg ? would that make the answer (3,45)

kind regards lakitu

- #5

Integral

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Look again at the radial component. How far is it from the origin to (3,3)?

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- #8

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- #9

Integral

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Would you please show us the relationship between polar and cartesian coordinates.

- #10

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so would the answer be (4.24,45deg)?

i did read your recomendations but struggled to figure those out :)

am i on the right lines ?

- #11

PPonte

But you could use instead of the approximated 4.24 the precise r, which is [tex]3\sqrt{2}[/tex].

- #12

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wow at last! I think i am going to have to change my username after this topic!

thanks

thanks

- #13

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Could you explain to me how you work out that the precise r is [tex]3\sqrt{2}[/tex] ?

Thank you

Thank you

- #14

Integral

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What is the length of the hypotenus of a right triangle when both of the other sides have length 1?

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- #16

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i get it AC^ = AB^ + BC^ :)

- #17

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no i stll dont get it:(

- #18

Integral

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- #19

VietDao29

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Uhmm, I suggest you reading your textbook again. There should be some chapter about the distance betweeen 2 points in Cartesian coordinate. The distance between 2 points P(xlakitu said:no i stll dont get it:(

[tex]d = PQ = \sqrt{(x_P - x_Q) ^ 2 + (y_P - y_Q) ^ 2}[/tex].

Now apply this, adn see if you can work out [tex]r = 3 \sqrt{2}[/tex].

Remember that the origin O is (0, 0).

Can you go from here? :)

Last edited:

- #20

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You were on the right track with this. If you have a point, (3, 3), you can use this theorem to work out the length of the hypotenuse, which is the distance between (3, 3) and the origin.lakitu said:i get it AC^ = AB^ + BC^ :)

- #21

PPonte

lakitu, maybe you are not visualising well. Hope this image helps.

http://img72.imageshack.us/img72/2572/radial7nd.gif [Broken]

http://img72.imageshack.us/img72/2572/radial7nd.gif [Broken]

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