Cat & Fishbowl Refraction Problem

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SUMMARY

The Cat & Fishbowl Refraction Problem involves calculating the perceived distance of a cat's face from a goldfish inside a 50 cm diameter spherical fish bowl. Using the lens maker's equation, the fish perceives the cat's face as being 36.14 cm from the edge of the bowl. This calculation assumes the refractive indices of water (1.33) and air (1.00) and ignores the glass wall of the bowl. The conclusion confirms that the fish sees the cat's face outside the bowl at this distance.

PREREQUISITES
  • Understanding of refraction principles
  • Familiarity with the lens maker's equation
  • Knowledge of refractive indices (e.g., water and air)
  • Basic geometry of spherical shapes
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  • Study the derivation and applications of the lens maker's equation
  • Explore the concept of virtual images in optics
  • Learn about the effects of different refractive indices on light behavior
  • Investigate real-world applications of refraction in aquatic environments
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Students studying optics, physics educators, and anyone interested in understanding light behavior in different mediums.

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Homework Statement


A goldfish lives in a 50 cm diameter spherical fish bowl. The fish sees a cat watching it. If the cat's face is 20 cm from the edge of the bowl, how far from the edge does the fish seet it as being? (You can ignore the thin glass wall of the bowl).


Homework Equations





The Attempt at a Solution


(n1)/s + (n2)/s' = (n2-n1)/R

(1.0)/20cm + (1.33)/s' = (1.33-1.00)/(25cm)

s'= -36.14 cm The fish will see a virtual image of the cat's face inside the bowl 36.14 cm. Is this correct, or can only an observer from outside the bowl see this virtual image?
 
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no... actually nevermind... the fish sees the cat's face outside the bowl 36.14 cm
 

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