(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A fish is 10 cm from the front surface of a spherical fish bowl

of radius 20 cm. (a) How far behind the surface of the bowl does the fish appear

to someone viewing the fish from in front of the bowl? (b) By what distance does

the fishâ€™s apparent location change (relative to the front surface of the bowl) when

it swims away to 30 cm from the front surface?

2. Relevant equations

(n1/s)+(n2/s')=(n2-n1)/r

3. The attempt at a solution

This problem was in the solution manual. It is one part that I don't understand. for s (object distance) they had it as -10cm, not +10cm. Why is that? In the book, the definition is that "s is positive for objects on the incident-light side of the surface" for refraction. Is this one different because the person is viewing from the other side the fish is on thus flipping the signs?

1. The problem statement, all variables and given/known data

2. Relevant equations

3. The attempt at a solution

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# Homework Help: A fish is 10 cm from the front surface of a spherical fish bowl

**Physics Forums | Science Articles, Homework Help, Discussion**