Catalyst increasing both forward and reverse reaction rate

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SUMMARY

The addition of a catalyst to a reaction at equilibrium increases the rates of both the forward and reverse reactions equally, confirming that the correct answer is D. This principle is fundamental in chemical kinetics, as catalysts lower the activation energy for both pathways without shifting the equilibrium position. The misconception that a catalyst favors one direction over the other is clarified through the understanding of reaction dynamics.

PREREQUISITES
  • Basic understanding of chemical equilibrium
  • Knowledge of reaction kinetics
  • Familiarity with catalysts and their role in chemical reactions
  • Concept of activation energy
NEXT STEPS
  • Study the principles of chemical equilibrium in detail
  • Explore the role of catalysts in various chemical reactions
  • Learn about the Arrhenius equation and its application to reaction rates
  • Investigate the concept of activation energy and its impact on reaction dynamics
USEFUL FOR

Chemistry students, chemical engineers, and professionals involved in reaction optimization and kinetics will benefit from this discussion.

TT0
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Please post this type of questions in the HW section using the template.
The question is:

Which takes place when a catalyst is added to a reaction at equilibrium?

A. The point of equilibrium is shifted to the right.
B. The point of equilibrium is shifted to the left.
C. The forward and reverse reactions rates are increased unequally.
D. The forward and reverse reactions rates are increased equally.
E. The value of ΔH has the same magnitude but a different sign.

I chose C because I think that a catalyst would increase the reaction rate of one way. The other way would also increase a bit because of the increased concentration of it. However, the answer is D, they both increase equally. I don't understand how this is possible, could someone explain this?

Thanks
 
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