Catapult Lab could someone assist me?

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    Catapult Lab
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SUMMARY

The discussion focuses on solving a physics problem related to projectile motion, specifically using the equations of motion to determine the time taken to cross a vertical distance of 104 meters. Key equations mentioned include y = Voy * t + 1/2(9.8)t^2 for vertical displacement and VFy^2 = Voy^2 + 2gy for final velocity. The user is encouraged to calculate the time by first determining the vertical component of the initial velocity using the angle of projection. The community member DLovas is welcomed and prompted to engage with the problem-solving process.

PREREQUISITES
  • Understanding of projectile motion principles
  • Familiarity with kinematic equations
  • Basic trigonometry for resolving velocity components
  • Knowledge of gravitational acceleration (9.8 m/s²)
NEXT STEPS
  • Review the derivation of kinematic equations for projectile motion
  • Practice problems involving vertical and horizontal motion components
  • Explore the impact of different launch angles on projectile trajectories
  • Learn about the effects of air resistance on projectile motion
USEFUL FOR

Students studying physics, educators teaching projectile motion concepts, and anyone seeking to improve their problem-solving skills in kinematics.

DLovas
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Homework Statement



http://i.minus.com/i725WMEqetlYA.jpg

Homework Equations



y=Voy * t + 1/2(9.8)t^2
VFy^2=Voy^2 + 2gy
Vox=Magnitude(Cos(Angle))
Voy=Magnitude(Sin(Angle))


The Attempt at a Solution



No clue
 
Last edited by a moderator:
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Welcome to PF!

Hi DLovas! Welcome to PF! :smile:

(try using the X2 button just above the Reply box :wink:)

Start by finding how long it will take to cross the 104 m vertical line. :smile:
 

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