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Cauchy's equation in terms of material acceleration

  1. Nov 10, 2015 #1
    Does anyone know which formula is used or how to arrive at the righthand side of the equation below, which is the dot product of del and rho*a 2nd order tensor(V V).
    . represents dot product
    and X a vector quantity
    This problem is in connection with transforming cauchy's equation in terms of the material acceleration

    del . (rho*V V) = {V*del . (rho*V) } + {rho*(V . del)*V}

    Thanks
     
  2. jcsd
  3. Nov 10, 2015 #2
    It's basically application of the derivative of a product rule in a situation in which you are dealing with vectors. The easiest way to prove to yourself that the identity is correct is to write it out in cartesian component form.

    Chet
     
  4. Nov 10, 2015 #3
    Thanks will give that a go
     
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