Cavity resonances between two long parallel plates

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SUMMARY

The discussion focuses on the acoustic resonances between two infinitely long parallel plates separated by a distance d, filled with a fluid that supports acoustic waves. The wavelengths of the resonant modes are defined as λ1 = 2d/1, λ2 = 2d/2, and λ3 = 2d/3. When the plates are not infinitely long in the X-direction, the boundary conditions change, leading to potential radiation losses and altered resonant frequencies. The analysis suggests that normal mode analysis may not be effective due to the open boundaries, and appropriate boundary conditions must be assumed to compute the normal modes accurately.

PREREQUISITES
  • Understanding of acoustic wave propagation in fluids
  • Knowledge of boundary conditions in wave mechanics
  • Familiarity with normal mode analysis techniques
  • Concept of radiation losses in resonant systems
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  • Research the effects of finite boundary conditions on acoustic resonances
  • Learn about normal mode analysis for open systems
  • Investigate radiation losses in acoustic cavities
  • Explore computational methods for simulating acoustic wave propagation
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Acoustic engineers, physicists studying wave mechanics, and researchers involved in the design of acoustic resonators will benefit from this discussion.

nawidgc
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Consider two rigid and infinitely long parallel plates (say they are of infinite length in X direction, so running from -inf to +inf in X axis) separated by a distance d (say measured in Y-direction). Let the space between the plates be filled up with a fluid that supports acoustic waves. If we somehow setup the resonance of acoustic wave, the wavelengths corresponding to successive resonant modes are:

λ1 = 2d/1
λ2 = 2d/2
λ3 = 2d/3
and so on.

How does the wavelength change when the plates are no longer of infinite extent in X-direction? If the dimension in X-direction is of the same order as d, what effect would this have on the resonant frequencies/wavelengths?
 
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The boundary conditions will be changed. There are now edges or interfaces normal to x. What are these boundary conditions on these surfaces?
 
The surfaces normal to the x-direction are open to air outside whereas the plates themselves are rigid (normal component of particle velocity = 0).
 
And that air is a different fluid than the fluid between the plates ?
 
No - the medium between the plates and outside is the same, i.e., air.
 
BvU said:
And that air is a different fluid than the fluid between the plates ?
i suppose a normal mode analysis would not be useful as the cavity is not completely enclosed.
 
BvU said:
And that air is a different fluid than the fluid between the plates ?
Picture2.png
 
Paul Colby said:
You will have radiation losses.
Of course. So in that case, i would need to assume appropriate boundary condition at the exit surfaces of domain and compute the normal modes.
 
  • #10
nawidgc said:
Of course. So in that case, i would need to assume appropriate boundary condition at the exit surfaces of domain and compute the normal modes.
Depending on what accuracy you wish, yes. I would expect the geometry shown will have strong coupling to the outside world which will wash out the resonances. You might get some indication by assuming a perfectly absorbing x-boundary.
 

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