Ceiling Fan Blade Acceleration and Angle Calculation

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SUMMARY

The discussion focuses on calculating the total acceleration and angle of a ceiling fan blade, given a radius of 0.318 m, an initial angular velocity of +1.48 rad/s, and an angular acceleration of +2.22 rad/s². After 0.394 seconds, participants derived the total acceleration using the formula total a = √((rω²)² + (rα)²). The correct final angular velocity was determined to be 2.35 rad/s, leading to accurate calculations for both parts of the problem.

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eiriyuki
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1. The blades of a ceiling fan have a radius of 0.318 m and are rotating about a fixed axis with an angular velocity of +1.48 rad/s. When the switch on the fan is turned to a higher speed, the blades acquire an angular acceleration of +2.22 rad/s2. After 0.394 s have elapsed since the switch was reset, what is (a) the total acceleration (in m/s2) of a point on the tip of a blade and (b) the angle between the total acceleration and the centripetal acceleration (See Figure)?

http://edugen.wiley.com/edugen/courses/crs2216/art/qb/qu/c08/w1590int.gif

Homework Equations


I tried using equation \omega_{2} = \omega^{2}_{o} + 2\alpha\theta

The Attempt at a Solution


This is the first time I have used the forums and I'm having a hard time putting in equations and things, so I apologize if the format is silly. I solved for theta in the above equation and my answers were 3.6509 (part a) rev and 14.153 (part b). I do not know if this is right, and if it is, I am not sure how to convert it into degrees so I can figure the position on the wheel.
 
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eiriyuki said:
This is the first time I have used the forums and I'm having a hard time putting in equations and things, so I apologize if the format is silly. I solved for theta in the above equation and my answers were 3.6509 (part a) rev and 14.153 (part b).

Why did you solve for θ? You don't have ω2. You need to find ω2.

Use the other equations of rotational motion.

Also, how does the tangential acceleration aT relate to the angular acceleration α?

How does the centripetal acceleration relate to ω2?
 
Wow, that is silly. I put my work for another problem I was having trouble with.

For this problem I used, total a=\sqrt{(rw^{2})^{2} + (r\alpha)^{2}}

I worked out the problem and got 0.99m/s^{2}, which was incorrect.
 
What value did you use ω?
 
rock.freak667 said:
What value did you use ω?

1.48 rad/s
 
eiriyuki said:
1.48 rad/s

That's where you went wrong. You need to use the final angular velocity. It started out at 1.48 rad/s and then allowed to accelerate at 2.22 rad/s for 0.394s. How would you find the final angular velocity given the information?
 
rock.freak667 said:
That's where you went wrong. You need to use the final angular velocity. It started out at 1.48 rad/s and then allowed to accelerate at 2.22 rad/s for 0.394s. How would you find the final angular velocity given the information?


Would I use average angular acceleration?

w - w0 / t - t0

Which gives me 2.35 rad/s.
 
Now try it back in your equation.
 
I got the correct answer for both parts now! Thank you so much for you help! :)
 
Last edited:
  • #10
Use the other equations of rotational motion.

Also, how does the tangential acceleration aT relate to the angular acceleration α?

How does the
ceiling fan relate to ω2?
 

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