Celsius to Kelvin Conversion: Solving for T2

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gracy
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Homework Statement


At constant volume and number of moles T1/T2=P1/P2
As per ideal gas equation
So given data is T1=27 degree celsius
P1=80 Cm ,P2=120 Cm T2=?

Homework Equations


T2=P2/P1 multiplied T1

The Attempt at a Solution

:120 cm/80cm multiplied by 27 degree celsius
=40.5 degree celsius
It is wrong because if it is done for klelvin

120 cm/80cm multiplied by (27+273.15)[/B]
T2=450.225 K
This 450.225 K is when converted into celsius it gives 177.075 degree celsius
Thus T2=450.225 K=177.075 degree celsius "≠"40.5 degree celsius
where I am wrong?
 
The 177C is correct and the 40.5C is wrong. The ideal gas law only works with Kelvin temperature and is not supposed to work with Celsius temperature.

Chet
 
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gracy said:
So given data is T1=27 degree celsius
It seems that the expected answer was determined as though the data was already in Kelvin. Is there a possibility that you mistook it for celsius?

If not mistaken, then your answer appears correct.
 
NascentOxygen said:
It seems that the expected answer was determined as though the data was already in Kelvin. Is there a possibility that you mistook it for celsius?

If not mistaken, then your answer appears correct.
I did not understand.