Celsius to Kelvin Conversion: Solving for T2

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Homework Help Overview

The discussion revolves around the conversion of temperature from Celsius to Kelvin in the context of the ideal gas law, specifically focusing on the relationship between temperature and pressure at constant volume.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the implications of using Celsius versus Kelvin in the ideal gas law, questioning the correctness of the original poster's calculations and assumptions.

Discussion Status

Some participants have provided guidance regarding the necessity of using Kelvin for calculations involving the ideal gas law, while others seek clarification on the original poster's understanding of the temperature values used.

Contextual Notes

There is a noted confusion regarding the temperature units, with participants questioning whether the original poster mistook Celsius for Kelvin in their calculations.

gracy
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Homework Statement


At constant volume and number of moles T1/T2=P1/P2
As per ideal gas equation
So given data is T1=27 degree celsius
P1=80 Cm ,P2=120 Cm T2=?

Homework Equations


T2=P2/P1 multiplied T1

The Attempt at a Solution

:120 cm/80cm multiplied by 27 degree celsius
=40.5 degree celsius
It is wrong because if it is done for klelvin

120 cm/80cm multiplied by (27+273.15)[/B]
T2=450.225 K
This 450.225 K is when converted into celsius it gives 177.075 degree celsius
Thus T2=450.225 K=177.075 degree celsius "≠"40.5 degree celsius
where I am wrong?
 
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The 177C is correct and the 40.5C is wrong. The ideal gas law only works with Kelvin temperature and is not supposed to work with Celsius temperature.

Chet
 
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gracy said:
So given data is T1=27 degree celsius
It seems that the expected answer was determined as though the data was already in Kelvin. Is there a possibility that you mistook it for celsius?

If not mistaken, then your answer appears correct.
 
NascentOxygen said:
It seems that the expected answer was determined as though the data was already in Kelvin. Is there a possibility that you mistook it for celsius?

If not mistaken, then your answer appears correct.
I did not understand.
 

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