Center of Mass: Finding the Third Particle's Position

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shell4987
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Homework Statement


A 2.80 kg particle has the xy coordinates (-2.00 m, 0.950 m), and a 3.30 kg particle has the xy coordinates (0.672 m, -0.0440 m). Both lie on a horizontal plane. At what (a)x and (b)y coordinates must you place a 3.39 kg particle such that the center of mass of the three-particle system has the coordinates (-0.663 m, -0.527 m)?


Homework Equations





The Attempt at a Solution


I don't even know what equation I have to use to find this, I looked in the book and I can't find anything about it. Can anyone help me with this?
 
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Doc Al said:
You need to understand the basic definition of center of mass: Center of Mass

How do I find the coordinates of the center of mass if they already gave them to me though? I now know what equation to use but I don't know how to apply it to this problem.
 
shell4987 said:
How do I find the coordinates of the center of mass if they already gave them to me though? I now know what equation to use but I don't know how to apply it to this problem.

You must solve two equations for the coordinates of the final particle.
 
arildno said:
You must solve two equations for the coordinates of the final particle.

Now I'm confused which two equations do I use?

xcom=(m1x1+m2x2)/M and...?
 
You'll need one equation for the x-component and another for the y-component.
 
You have THREE particles here, not two!

YOu have, for the x's:
[tex]x_{c.m}=\frac{m_{1}x_{1}+m_{2}x_{2}+m_{3}x_{3}}{m_{1}+m_{2}+m_{3}}[/tex]

Now, in this expression, what quantities are KNOWN, which quantity (or quantities) is unknown?
 
arildno said:
You have THREE particles here, not two!

YOu have, for the x's:
[tex]x_{c.m}=\frac{m_{1}x_{1}+m_{2}x_{2}+m_{3}x_{3}}{m_{1}+m_{2}+m_{3}}[/tex]

Now, in this expression, what quantities are KNOWN, which quantity (or quantities) is unknown?

what's unknown is the ycom and the xcom... so i put my information in that equation and solved it and got xcom= -0.593 and ycom=0.0767 and they are wrong. i have no idea what I'm doing wrong here.
 
What's unknown are the coordinates of the third particle: x_3 and y_3. The coordinates of the center of mass are known.
 
Remember that your exercise can be equivalently rephrased into:
(First some blah&info about the two first particles)
..The common centre of mass of the three-particle system IS (-0.663,-0.527), and the mass of the third particle IS 3.39kg.
Question:
What is the position of the third particle?