Evaluate a Particle's Position at Given Times

  • Thread starter Thread starter AryRezvani
  • Start date Start date
  • Tags Tags
    Particles Position
Click For Summary

Homework Help Overview

The discussion revolves around evaluating the position of a particle moving along the x-axis, described by the equation x = 3t². Participants are tasked with finding the position at specific times and exploring the concept of velocity through limits.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss evaluating the position at a specific time and the implications of introducing a variable for Δt. There is confusion regarding how to handle Δt in the context of the problem.

Discussion Status

Some participants have attempted to substitute values into the equation and expand expressions, while others are questioning the approach to take with Δt and the meaning of Δx. Guidance has been offered regarding the use of symbols and the nature of the results expected.

Contextual Notes

There is an emphasis on understanding the change in position (Δx) and the need for symbolic manipulation rather than numerical answers for certain parts of the problem.

AryRezvani
Messages
65
Reaction score
0

Homework Statement



The position of a particle moving along the x-axis varies in time according to the expression x = 3t 2, where x is in meters and t is in seconds. Evaluate its position at the following times.
(
a) t = 2.30 s


(b) t = 2.30 s + Δt


(c) Evaluate the limit of Δx/Δt as Δt approaches zero to find the velocity at t = 2.30 s.
m/s


Homework Equations



Listed above.

The Attempt at a Solution



Well for part 'a)', I plugged in the given time (2.30) and got 15.87 meters.

At part 'b)' is where I get stumped. What would you do to find delta t?

Thanks.
 
Physics news on Phys.org
AryRezvani said:

Homework Statement



The position of a particle moving along the x-axis varies in time according to the expression x = 3t 2, where x is in meters and t is in seconds. Evaluate its position at the following times.
(
a) t = 2.30 s


(b) t = 2.30 s + Δt


(c) Evaluate the limit of Δx/Δt as Δt approaches zero to find the velocity at t = 2.30 s.
m/s


Homework Equations



Listed above.

The Attempt at a Solution



Well for part 'a)', I plugged in the given time (2.30) and got 15.87 meters.

At part 'b)' is where I get stumped. What would you do to find delta t?

Thanks.

You don't find Δt; You plug in the symbol Δt and expand the expression; at this point it is simply a variable. It may be worthwhile to replace the initial value of t (2.30s) with a symbol, too. Say, to = 2.30s. This may help keep the subsequent manipulations neat.

For part (c) you need to understand what is meant by Δx. That is, the change in x.
 
gneill said:
You don't find Δt; You plug in the symbol Δt and expand the expression; at this point it is simply a variable. It may be worthwhile to replace the initial value of t (2.30s) with a symbol, too. Say, to = 2.30s. This may help keep the subsequent manipulations neat.

For part (c) you need to understand what is meant by Δx. That is, the change in x.

Okay, so all you do is plug in the variables.

So I came up with X = 3(T+TΔ)^2

Would I FOIL it out, or something? How do I come up with a numerical answer?
 
I just foiled and got 3(5.29 + 4.60ΔT + ΔT^2)

Stuck here now, shoot. I have a feeling I'm way off...
 
AryRezvani said:
Okay, so all you do is plug in the variables.

So I came up with X = 3(T+TΔ)^2

Would I FOIL it out, or something? How do I come up with a numerical answer?

You don't. There's no numerical answer to this part unless a specific Δt is provided. A symbolic result is sometimes what you're looking for. Move on to the next part.
 

Similar threads

  • · Replies 13 ·
Replies
13
Views
2K
  • · Replies 18 ·
Replies
18
Views
6K
  • · Replies 9 ·
Replies
9
Views
13K
Replies
6
Views
3K
Replies
3
Views
983
Replies
8
Views
2K
  • · Replies 10 ·
Replies
10
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 40 ·
2
Replies
40
Views
4K
  • · Replies 2 ·
Replies
2
Views
2K