Centre-of-mass Energy of Colliding protons

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SUMMARY

The center-of-mass energy (Ecm) of two colliding protons at the Large Hadron Collider (LHC) can reach a total energy of 16 TeV when both protons are accelerated to 8 TeV. However, the actual achieved value is 4 TeV, with a design value of 7 TeV. When colliding protons with a stationary target, the energy required to achieve the same Ecm is greater due to the need to account for the motion of the center of mass. Understanding the relationship between total energy (Etot) and Ecm is crucial in particle physics.

PREREQUISITES
  • Understanding of relativistic energy equations, specifically E2 = (pc)2 + (E0)2
  • Knowledge of kinetic energy calculations, particularly KE = E - E0
  • Familiarity with the concept of center-of-mass energy in particle collisions
  • Basic principles of particle acceleration and collision dynamics at the LHC
NEXT STEPS
  • Research the implications of relativistic effects on particle collisions
  • Learn about the design and operational parameters of the LHC, including energy limits
  • Explore the differences between center-of-mass energy and laboratory frame energy in particle physics
  • Study the calculations involved in determining collision energy for particles at rest versus colliding particles
USEFUL FOR

Physicists, students of particle physics, and researchers involved in high-energy physics experiments, particularly those interested in the dynamics of proton collisions and energy calculations at the LHC.

joakley
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Homework Statement


LHC can accelerate proton beams to energies of 8Tev.
1. What is the centre-of-mass energy of two colliding protons?
2. What would be the beam energy needed if one wanted to reach the same centre-of-mass energy when colliding beam protons with protons in a target at rest?

Homework Equations



E2 = (pc)2+(E0)2

KE = E - E0

The Attempt at a Solution



Common sense tells me that two particles of equal mass and energy colliding head on results in all the energy of the particle transferring to "collision energy". So I assume an Etot = (8+8)TeV = 16TeV sounds reasonable unless I need to include rest mass energy, which i would have though is negligible. Does this Etot relate simply to Ecm?

I am having trouble understanding the loss of collision energy in the rest target case, surely all energy supplied to the particle for momentum must be conserved/transferred to the rest proton and there is no center-of-mass energy? I guess my understanding of what Ecm (center-of-mass energy) may be throwing me off slightly?
 
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LHC can accelerate proton beams to energies of 8Tev.
This is wrong, the achieved value is 4 TeV and the design value is just 7 TeV. Anyway, does not matter here.

joakley said:
Common sense tells me that two particles of equal mass and energy colliding head on results in all the energy of the particle transferring to "collision energy". So I assume an Etot = (8+8)TeV = 16TeV sounds reasonable unless I need to include rest mass energy, which i would have though is negligible. Does this Etot relate simply to Ecm?
Right.
The rest energy is already included in the 8 TeV (negligible of course...).

I am having trouble understanding the loss of collision energy in the rest target case, surely all energy supplied to the particle for momentum must be conserved/transferred to the rest proton and there is no center-of-mass energy? I guess my understanding of what Ecm (center-of-mass energy) may be throwing me off slightly?
The center-of-mass system is moving here, there is always a reference frame where both protons have an opposite velocity of equal magnitude. In the lab, you need much more energy as you have to provide the CMS energy PLUS the energy for the motion of the center of mass.
 
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