Centrifugal (Ficticious) Force problem

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    Centrifugal Force
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SUMMARY

The discussion centers on calculating the forces acting on a rider in the Roundup amusement park ride, which features a 16m diameter rotating ring. The rider's mass is 55kg, and the ring completes one rotation every 4.5 seconds. At the top of the ride, the total force exerted by the ring on the rider combines gravitational force and centripetal force, while at the bottom, the forces act in opposition. The calculations reveal that understanding the relationship between mass, velocity, and radius is crucial for determining the forces involved.

PREREQUISITES
  • Centripetal force concepts
  • Basic physics of rotational motion
  • Force calculations using F = ma
  • Understanding of gravitational force
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  • Calculate the centripetal force at different points in the ride
  • Explore the effects of varying the rotation period on rider safety
  • Investigate the physics of amusement park ride design
  • Learn about the implications of mass and radius on centripetal acceleration
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Physics students, amusement park ride engineers, and anyone interested in the dynamics of rotational motion and safety in ride design.

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47. In an amusement park ride called the Roundup, passengers stand inside a 16m diameter rotating ring. After the ring has acquired suficient speed, it tilts into a vertical plane.

a. suppose the ring rotates once every 4.5 s. If a rider's mass is 55kg, with how much force does the ring pus on her at the top of the ride? At the bottom?

b. What is the longest rotation period of the wheel that will prevent the riders from falling off at the time?

I've calculated that the radius is 8m and the period T is equal to (1/4.5) or .22 revolutions per second. I'm completely stuck as to where to go from here. help?
 
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[tex]F = ma = m\frac{v^{2}}{r}[/tex]
 
At the top of the ride both the weight, [itex]W[/itex], and the "push force" [itex]F_P[/itex] on a passenger is directed towards the center of the ring. The combined effect of these two forces gives us the needed centripetal force [itex]F_C[/itex] to make the passenger go along with the ride so

[tex]F_P + W = F_C[/tex]
 

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