Centrifugal Force load caused from propeller rotation

Click For Summary
SUMMARY

The discussion focuses on calculating the centrifugal force generated by two propeller blades rotating at 2000 RPM with a diameter of 72 inches and a weight of 4 lbs per blade. The user intends to mill a Clark-Y profile on the blades, reducing the length by 4 inches for a bolted connection to the hub. The centrifugal force is critical for determining the yield strength of the bolted connection, which will be adjusted using shims to modify the pitch angle. The mass distribution from the center to the tip of the blades significantly influences the force calculation.

PREREQUISITES
  • Centrifugal force calculations
  • Understanding of propeller dynamics
  • Knowledge of Clark-Y airfoil profiles
  • Basic principles of materials science related to yield strength
NEXT STEPS
  • Research centrifugal force formulas for rotating objects
  • Study the effects of mass distribution on propeller performance
  • Learn about milling techniques for airfoil profiles
  • Explore methods for adjusting pitch angles in propeller design
USEFUL FOR

Aerospace engineers, propeller designers, and mechanical engineers involved in the design and optimization of rotating blades and propellers.

hovercraft57
Messages
8
Reaction score
0
Is anyone interested in telling me the force created from 2 propeller blades rotating 2000 rpm.The total diameter of the prop is 72 inches and the weight of 1 blade is 4 lbs.
Reason for the question is I want to mill a clark-y profile the length of the blade less ,4 inches for a bolted connection to the hub. The milled bar with the profile is to get twisted after milling to get the pitch.Using shims at the hub blade connection to increase/decrease pitch angle for final setting.
I'm going with the idea the bolted connection yield strength would be based on the centrifugal force of the rotating blades.
Help would be most appreciated,ED
 
Engineering news on Phys.org
The force will depend a lot on the mass distribution from the center to the tip. You will have to specify that. Clark Y only tells the cross section profile of the blade at each section. I don't think that matters.
 
the section of the blade is the same 4 inches from the centre to the tip. The lbs/inch is .1111/1 inch of the aluminum flat bar used for a blade. there are 2 blades. I thought not using the weight /inch of the clark -y section would give a ssafety margin. Thanks ED
 

Similar threads

  • · Replies 15 ·
Replies
15
Views
3K
  • · Replies 2 ·
Replies
2
Views
10K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
Replies
1
Views
4K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
5
Views
4K
  • · Replies 7 ·
Replies
7
Views
3K