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Centripetal Acceleration of North Pole

  1. Oct 27, 2008 #1
    1. The problem statement, all variables and given/known data
    Consider the radius of the Earth to be 6.38×106 m. What is the magnitude of the centripetal acceleration experienced by a person (a) at the equator and (b) at the North Pole due to the Earth's rotation?


    2. Relevant equations
    a = V^2 / r


    3. The attempt at a solution
    I drew a diagram of what the problem describes but how do you get the acceleration without knowing the velocity?? Would it have something to do with angular speed??
     
  2. jcsd
  3. Oct 27, 2008 #2

    Doc Al

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    Staff: Mentor

    Exactly. You can express the centripetal acceleration in terms of angular speed. (How does angular speed relate to velocity for circular motion?)
     
  4. Nov 12, 2008 #3
    angular = radians / s
     
  5. Nov 12, 2008 #4
    Wouldnt you need to know the time for angular velocity?
     
  6. Nov 12, 2008 #5

    Doc Al

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    Staff: Mentor

    Radians/sec are certainly the units for angular velocity, but I was thinking of the relationship between angular velocity and tangential velocity. Read this: Angular Velocity

    What's the angular velocity of the Earth's rotation?
     
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