Centripetal force ball on a string lab

Click For Summary

Homework Help Overview

The discussion revolves around a physics lab involving centripetal force, where a mass is spun in a circular motion using a string attached to a plastic tube. Participants are tasked with deriving an expression for centripetal force (Fc) in relation to the angle (theta) and radius of the circular path.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the relationship between the forces acting on the mass, including the tension in the string and gravitational force. There is an attempt to connect the centripetal force to the forces acting on both the small mass and the mass at the bottom of the setup. Questions arise regarding the setup and the role of the angle theta in the analysis.

Discussion Status

The discussion is ongoing, with participants exploring different aspects of the problem. Some have suggested drawing diagrams to clarify the forces involved, while others are questioning how the components of tension relate to the centripetal force required for circular motion.

Contextual Notes

There is mention of a diagram that could aid in understanding the setup, and participants are considering the implications of the angle of the string on the forces involved. The original poster expresses uncertainty about how to begin formulating the equation for centripetal force.

Revengeance
Messages
22
Reaction score
0

Homework Statement


So referring to this lab , http://static3.mbtfiles.co.uk/media...ureate/physics/824297/html/images/image12.pngIn this lab you are holding the plastic tube and twirling it to make the small mass spin in a circle. Keep in mind there is a mass on the bottom.

I have to create an expression for Fc with theta and radius.

Homework Equations



Fc = 4pi^2rf^2 * m

The Attempt at a Solution


Well from the FBD of the small mass, we know that FC = FT

and from the FBD of the mass at the bottom we know that FT=FG.

Therefore for the system, wouldn't FC = FG of the mass on the bottom?

As for the equation i am not really sure were to start, could someone help me out please.
 
Physics news on Phys.org
The string attached tot the mass going in a circle is angled downwards a bit, that is the horizontal plane in which the mass is circling is a bit below the top of the tube. That is the theta that is mentioned. Best to draw a diagram and post it.
 
so i know the lab looks something like this, and the Fg of the small mass will cancel out the fty in the tension, therefore ftx controlling the motion.
 

Attachments

  • lab.png
    lab.png
    3.1 KB · Views: 615
Yes, the x component provides the centripetal force.
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
1K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 5 ·
Replies
5
Views
4K
  • · Replies 9 ·
Replies
9
Views
5K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 17 ·
Replies
17
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 1 ·
Replies
1
Views
4K
Replies
27
Views
4K